Spring Acceleration: Does Velocity = 0 Mean a = 0?

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SUMMARY

The discussion centers on the relationship between velocity and acceleration in the context of a mass attached to a spring undergoing simple harmonic motion (S.H.M). At the lowest point of the spring's motion, the velocity is indeed zero; however, the acceleration is not zero due to the nature of S.H.M. The acceleration at this point is directed upwards and is equal to g, the acceleration due to gravity. This is because, at the lowest point, the displacement (x) is at its maximum, resulting in maximum acceleration according to the formula a = -ω²x.

PREREQUISITES
  • Understanding of simple harmonic motion (S.H.M.)
  • Familiarity with the concepts of velocity and acceleration
  • Knowledge of the relationship between displacement and acceleration in S.H.M.
  • Basic calculus, specifically differentiation (dv/dt = a)
NEXT STEPS
  • Study the principles of simple harmonic motion (S.H.M.) in detail
  • Learn about the mathematical derivation of acceleration in S.H.M. using a = -ω²x
  • Explore the implications of maximum displacement on acceleration in oscillatory systems
  • Investigate the role of gravitational acceleration (g) in various physical systems
USEFUL FOR

Physics students, educators, and anyone interested in understanding the dynamics of oscillatory motion and the principles of simple harmonic motion.

IKonquer
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Lets say you attach a weight to a spring and release it from rest. When the spring reaches its lowest point, its velocity is zero. What I am confused about is the acceleration of the spring at the bottom. My professor said that the acceleration of the weight at the bottom is g upwards. Intuitively that makes sense to me but not mathematically. dv/dt = a. And if the velocity is 0 at that instant, shouldn't the acceleration also be zero?

Thanks in advance.
 
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a=dv/dt is right. But since the mass executes S.H.M, a=-ω2x.
When the mass reaches its lowest point, x is not 0. Infact, x is max and hence a is max.
Acceleration is instantaneosly 0 only when it crosses its mean position.
 
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