Spring mass spring mass spring - 2 balls oscillations

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Both masses are in point.

I need to count displacement x(t) but I don't know how to write derivative equations? Could someone help? Or at least give me a tip?
 
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Are we to include gravity or can we think of this as horizontal? Can we assume that the two masses are equal? Can we assume that the two springs have the same spring constant and natural length?

Assuming all of that, let x_1 be the distance from the lower edge to the center of mass of the first ball, x_2 be the distance from the lower edge to the center of mass of the second ball and let m be the mass of each ball. Let L be the distance from the lower edge to the upper, let k be the spring constant of each spring and let l be their natural lengths.

"F= ma" of course, so m d^2x_1/dt^2 is equal to the total force on the first mass. There is a force from the spring below it equal to the spring contant times its extension: -k(x_1- l). There is a force from the spring above it, equal to the spring constant times its extension: k(x_2- x_1- l) (positive because if the spring is stretched, it will pull the mass upward).
m\frac{d^2x_1}{dt^2}= -k(x_1-l)+ k(x_2- x_1- l)= -2kx_1+ kx_2

md^2x_2/dt^2 is equal to the total force on the second mass. There is a force from the spring below it of -k(x_2-x_1- l), equal and opposite to the force of that spring on the lower mass. There is a force from the spring above it: k(L- x_2- l.
m\frac{d^2 x_2}{dt^2}= -k(x_2-x_1-l)+ k(L- x_2- l)= -2kx_2+ kx_1+ kL[/itex].<br /> <br /> Those are your two equations. When you solve them, you should find that you have <b>two</b> &quot;natural frequencies&quot;, \sqrt{k/m} and \sqrt{3k/m}.-
 
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