Square loop of wire surrounding a solenoid

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SUMMARY

A square loop of wire with a side length of 0.1 m surrounds a solenoid with 500 turns and a length of 0.3 m. The solenoid has a radius of 0.025 m and a current increasing at a rate of 0.7 A/s. The resistance of the square loop is 30 Ω. The induced electromotive force (emf) in the loop can be calculated using the formula e = -dΦB/dt = A * dB/dt, where A is the area of the solenoid. The area of the solenoid, which is critical for calculating the induced current in the loop, is determined to be 0.001 m².

PREREQUISITES
  • Understanding of electromagnetic induction principles
  • Familiarity with solenoid characteristics and formulas
  • Knowledge of calculating area for circular cross-sections
  • Basic proficiency in Ohm's Law and circuit analysis
NEXT STEPS
  • Calculate the induced current in the square loop using the derived emf
  • Explore the relationship between magnetic flux and induced current in loops
  • Learn about the effects of resistance on induced currents in circuits
  • Study the applications of solenoids in electromagnetic devices
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Physics students, electrical engineers, and anyone interested in understanding electromagnetic induction and its applications in circuits.

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A square loop of wire surrounds a solenoid. The side of the square is 0.1 m, while the radius of the solenoid is 0.025 m. The square loop has a resistance of 30 W. The solenoid has 500 turns and is 0.3 m long. The current in the solenoid is increasing at a constant rate of 0.7 A/s. What is the current flowing in the square loop?



e = -DFB/Dt = A*DB/Dt
e = A*(m0nDI)/Dt



I cannot figure out what the area the equation is talking about. I substituted 500 for n and .7 for change in I over change in T but the area i have which i thought was .001m^2 i don't think is right. help!
 
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The area is the area inside the solenoid, since this is the only place where there is an external magnetic field.
 

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