Square metric not satisfying the SAS postulate

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SUMMARY

The discussion centers on demonstrating that R² with the square metric does not satisfy the SAS (Side-Angle-Side) Postulate. The square metric distance is defined as D((x1, y1), (x2, y2)) = max{|x2 − x1|, |y2 − y1|}. An example is provided using two triangles: the first triangle with vertices (0,0), (1,0), and (0,1) has all sides of metric length 1, while the second triangle, obtained by rotating the first by 45 degrees to points (0,0), (1,1), and (1,-1), has side lengths of 1, 1, and 2. This discrepancy in side lengths illustrates the failure of the SAS Postulate under the square metric.

PREREQUISITES
  • Understanding of R² geometry
  • Familiarity with the square metric distance
  • Knowledge of the SAS Postulate in triangle congruence
  • Basic concepts of angle measurement in Euclidean space
NEXT STEPS
  • Explore the implications of non-Euclidean metrics in geometry
  • Study triangle congruence criteria beyond SAS, such as SSS (Side-Side-Side)
  • Investigate other metrics in R², such as the Euclidean metric
  • Learn about transformations in geometry, including rotations and their effects on congruence
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Mathematicians, geometry students, educators, and anyone interested in the properties of metrics and triangle congruence in different geometric contexts.

pholee95
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I'm not sure on how to do this problem. Can someone please help and explain? Thank you!

Recall (Exercise 3.2.8) that the square metric distance between two points (x1, y1) and
(x2, y2) in R^2 is given by D((x1, y1), (x2, y2))= max{|x2 − x1|, |y2 − y1|}. Show by
example that R^2 with the square metric and the usual angle measurement function does
not satisfy the SAS Postulate.
 
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pholee95 said:
I'm not sure on how to do this problem. Can someone please help and explain? Thank you!

Recall (Exercise 3.2.8) that the square metric distance between two points (x1, y1) and
(x2, y2) in R^2 is given by D((x1, y1), (x2, y2))= max{|x2 − x1|, |y2 − y1|}. Show by
example that R^2 with the square metric and the usual angle measurement function does
not satisfy the SAS Postulate.

Hi pholee95! Welcome to MHB! ;)

Let's pick a simple triangle, like a rectangular one with points (0,0), (1,0), (0,1).
Now let's rotate it by 45 degrees, keeping the angles the same, and keeping the lengths of the side according to the metric the same.
Then we'll get the triangle with points (0,0), (1,1), (1,-1).
According to the SAS postulate it should then be congruent.
But congruency requires that the lengths of all sides are the same. Is the (metric) length of the 3rd side the same?
 
I like Serena said:
Hi pholee95! Welcome to MHB! ;)

Let's pick a simple triangle, like a rectangular one with points (0,0), (1,0), (0,1).
Now let's rotate it by 45 degrees, keeping the angles the same, and keeping the lengths of the side according to the metric the same.
Then we'll get the triangle with points (0,0), (1,1), (1,-1).
According to the SAS postulate it should then be congruent.
But congruency requires that the lengths of all sides are the same. Is the (metric) length of the 3rd side the same?

No it won't be the same. Right?
 
pholee95 said:
No it won't be the same. Right?

Correct. All sides of the first triangle have metric length 1.
But the second triangle has metric lengths 1, 1, and 2.
 

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