Stability of rigid body rotation about different axes

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Homework Help Overview

The discussion revolves around the stability of rigid body rotation about different axes, particularly focusing on the relationship between moment of inertia and stability. Participants explore the differences in behavior between rigid and non-rigid bodies in terms of rotational stability.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Some participants attempt to reconcile the stability of rotation for rigid bodies versus non-rigid bodies, questioning the generalizations made about moment of inertia. Others reference the 'tennis racket theorem' and apply Euler's equations to analyze stability, while some express confusion about the implications of equal moments of inertia.

Discussion Status

The discussion is active, with participants providing insights and questioning assumptions. Some guidance has been offered regarding the application of the perpendicular axis theorem, and there is an exploration of different interpretations of stability in rigid bodies.

Contextual Notes

Participants note that the object in question has negligible thickness, allowing it to be treated as a lamina, which may influence the moments of inertia being discussed. There is also mention of specific shapes, such as disks versus spheres, which may affect the analysis.

Leo Liu
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We know that for a non-rigid body, the most stable type of rotation of it is the rotation about the axis with the maximum momentum of inertia and thus the lowest kinetic energy. However, for this question involving a rigid body, the most stable axis is the one with the lowest moment of inertia. Why is it so?
 
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Leo Liu said:
We know that for a non-rigid body, the most stable type of rotation of it is the rotation about the axis with the maximum momentum of inertia and thus the lowest kinetic energy. However, for this question involving a rigid body, the most stable axis is the one with the lowest moment of inertia. Why is it so?
I'm no expert but I don't follow what you have written. If you look-up 'tennis racket theorem' you should find it helpful.
 
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Steve4Physics said:
I'm no expert but I don't follow what you have written. If you look-up 'tennis racket theorem' you should find it helpful.
Here is my reasoning I came up with after looking at the wiki article:
This object has two axes whose inertias are equal. So the rotation about either of these axes is unstable. If we apply euler's equations to this question, the functions of the angles will not show periodicity and will diverge; thus it is unstable.
Your reply is helpful. Thanks.
 
Leo Liu said:
We know that for a non-rigid body, the most stable type of rotation of it is the rotation about the axis with the maximum momentum of inertia and thus the lowest kinetic energy.
We do? I would not have thought one could be so general about rotation of non-rigid bodies.
For rigid bodies, the max and min are both stable.
Leo Liu said:
This object has two axes whose inertias are equal.
Not so.
 
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Leo Liu said:
This object has two axes whose inertias are equal.
The question says the thickness is negligible. So we can treat the object as a lamina and use the perpendicular axis theorem. That should help you to establish the 3 moments of inertia are different and their relative sizes.
 
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haruspex said:
We do? I would not have thought one could be so general about rotation of non-rigid bodies.
For rigid bodies, the max and min are both stable.
Well I was thinking that a non rigid body might dissipate energy through heat. But yeah what I said was too absolute.
haruspex said:
Not so.
Sorry just realized they are disks as opposed to spheres. :oops:
 

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