B Is the Stairmaster a Valuable Exercise Tool Despite Physics Misconceptions?

  • B
  • Thread starter Thread starter MasterTheStairs
  • Start date Start date
  • Tags Tags
    Physics
AI Thread Summary
The discussion centers on the exercise value of the Stairmaster, addressing misconceptions about its physics, particularly the claim that it has no value because the steps fall away. The consensus is that as long as users apply muscular force, work is being done, regardless of the relative motion of the steps. It's noted that using handholds can reduce the effectiveness of the workout, similar to being assisted uphill. The definition of work (force times distance) is emphasized as a clear way to explain its value to clients. Overall, the Stairmaster is recognized as a legitimate exercise tool when used correctly.
MasterTheStairs
Messages
4
Reaction score
5
Apologies if this is a repeat of previous threads, I did search and can't see an answer to my question.

I'm a fitness trainer and a subject that comes up with clients from time to time is the physics of the stairmaster. Confusion reigns as some influential commentators have said that it has no exercise value "as the step is falling away". I'm satisfied that they just betray a very incomplete understanding of the physics, as the fact is that so long as the relative positions of the mass and point of application of the force are either forced apart (as in a squat), maintain their distance (as in any isometric exercise or the paused phase at the top and bottom of a squat just before lowering or return) or only allowed to come together at a controlled rate (as in the eccentric phase of a movement or the deliberate slowing of a movement like the squat mid-exercise, or where there is force being applied which is less than the mass, so that the force is overcome and the mass moves anyway) by virtue of the application of muscular force, then work is being done and exercise value is achieved. The fact that most of the mass of the body maintains its position is irrelevant. Besides my understanding of the physics, the fact that anyone using a stairmaster sweats, pants and gets tired is evidence that work is being done.

So;
Am I broadly correct in my understanding of the physics?
If not, what am I missing?
Is there any easier way to explain this to clients or a resource I could post them to?

TIA for any help, it'll all be appreciated.
 
  • Like
Likes PeroK
Physics news on Phys.org
  • Like
Likes russ_watters
MasterTheStairs said:
Apologies if this is a repeat of previous threads, I did search and can't see an answer to my question.

I'm a fitness trainer and a subject that comes up with clients from time to time is the physics of the stairmaster. Confusion reigns as some influential commentators have said that it has no exercise value "as the step is falling away". I'm satisfied that they just betray a very incomplete understanding of the physics, as the fact is that so long as the relative positions of the mass and point of application of the force are either forced apart (as in a squat), maintain their distance (as in any isometric exercise or the paused phase at the top and bottom of a squat just before lowering or return) or only allowed to come together at a controlled rate (as in the eccentric phase of a movement or the deliberate slowing of a movement like the squat mid-exercise, or where there is force being applied which is less than the mass, so that the force is overcome and the mass moves anyway) by virtue of the application of muscular force, then work is being done and exercise value is achieved. The fact that most of the mass of the body maintains its position is irrelevant. Besides my understanding of the physics, the fact that anyone using a stairmaster sweats, pants and gets tired is evidence that work is being done.

So;
Am I broadly correct in my understanding of the physics?
If not, what am I missing?
Is there any easier way to explain this to clients or a resource I could post them to?

TIA for any help, it'll all be appreciated.

Yes, it's easy to get it wrong. I got very confused when I first analysed it. There's no doubt, however, that the work done is essentially the same whether the stairs are moving down, or you are moving up the stairs.

The key physics argument is to consider the (inertial) reference frame moving down with the stairs. I don't know if there is a better argument that is more accessible to lay-people.

However, use of any external aids that are not moving down (e.g. the hand holds) does make a difference. To get the full value you mustn't pull on anything that is not descending. The people you see on the treadmill holding the bars, or pushing down on the handholds on the stairmaster are significantly reducing the work done. That's similar to being pulled uphill by a ski-tow.
 
  • Like
Likes MasterTheStairs and jbriggs444
MasterTheStairs said:
Am I broadly correct in my understanding of the physics?
Yes.
Is there any easier way to explain this to clients or a resource I could post them to?
Other than the links @anorlunda provided, the definition of work is the simplest way to explain it: work = force x distance. The fact that it is the treadmill/stairmaster that is "moving" and not the user doesn't matter as long as your foot applies the same force over the same distance.

Or if you really want to blow their minds, you can point out that "moving" is a relative thing. It is perfectly acceptable to declare the stairmaster/treadmill to be stationary and the person to be moving.
 
  • Like
Likes MasterTheStairs
At the risk of living up to my name:

I believe that for the case of a treadmill/stairmaster, the effort is not trivial, but also not as large as the requirement for the equivalent fixed apparatus. Consider a user's leg (since that's what we're really talking about):
In the case of a fixed stair, the leg starts bent at the knee, the weight is shifted to that leg, and the entire body is elevated as the leg straightens. The leg 'sees' the weight of the body plus the force required to accelerate the body mass to the gravitationally superior position.

In the case of a 'stairmaster,' the motion looks the same, but the force on the leg is (at most) the weight of the body, and probably slightly less.

In short: The 'F' in the 'FdotdS' is smaller on a stairmaster.
 
  • Like
Likes MasterTheStairs
Dullard said:
At the risk of living up to my name:

I believe that for the case of a treadmill/stairmaster, the effort is not trivial, but also not as large as the requirement for the equivalent fixed apparatus. Consider a user's leg (since that's what we're really talking about):
In the case of a fixed stair, the leg starts bent at the knee, the weight is shifted to that leg, and the entire body is elevated as the leg straightens. The leg 'sees' the weight of the body plus the force required to accelerate the body mass to the gravitationally superior position.

In the case of a 'stairmaster,' the motion looks the same, but the force on the leg is (at most) the weight of the body, and probably slightly less.

In short: The 'F' in the 'FdotdS' is smaller on a stairmaster.

Although appealing, that argument depends on the motion through the gravitational field being relevant. If you had three sets of stairs: one moving up, one at rest relative to the Earth's surface; and one moving down, then you wouldn't be able to tell which one you were on.

The point is that regarding the gravitational field you cannot distinguish between these three cases.
 
  • Like
Likes MasterTheStairs
I'm not sure that I follow your reasoning. Were I on one of the 3 stairs in your thought experiment, I would certainly be able to distinguish between them, unless my body was also moving at the experimental velocity. I understand what you're saying, but don't believe that the stairmaster (or treadmill) is equivalent to any of your 3 cases. The fundamental question is: is more work required to lift a body some distance than to maintain elevation as the 'floor' falls away? I say 'yes' (timidly).
 
  • Like
Likes MasterTheStairs
Dullard said:
I'm not sure that I follow your reasoning. Were I on one of the 3 stairs in your thought experiment, I would certainly be able to distinguish between them, unless my body was also moving at the experimental velocity. I understand what you're saying, but don't believe that the stairmaster (or treadmill) is equivalent to any of your 3 cases. The fundamental question is: is more work required to lift a body some distance than to maintain elevation as the 'floor' falls away? I say 'yes' (timidly).

Certainly there is the potential for the interaction between your work and the stairmaster engine to create a difference between the two cases. And that, I believe, gets complicated. But, as far as the raw movement through a gravitational field is concerned, you cannot distinguish the cases.

Imagine you were in an elevator moving down at constant speed. And the elevator had some internal steps. You could not tell that the elevator was moving down and you were climbing steps moving down in the gravitational field. That would feel exactly like climbing the same steps with the elevator at rest or moving upwards at constant speed.

The basic operation of the stairmaster is the same. If you do nothing, you move down with the stairs. And, to avoid moving down with the stairs you have to climb them in the same way as you have to climb a stationary flight of stairs.
 
  • Like
Likes MasterTheStairs
As I said, I understand what you're saying. I have no issue with your elevator. My problem is with your last paragraph. I don't agree that the fact that I'll 'move down with the stairs' if I 'do nothing' makes the stairmaster equivalent to the 'whole system in an elevator'. I don't believe that 'you have to climb them in the same way.' It still boils down to the magnitude of the force on a leg. If climbing stairs were a series of infinitely fast exertions, where you 'pop' to the next step, I'd agree that the stairmaster is equivalent to stairs. The actual motion is (more or less) continuous - that leads to the difference is the required force - station-keeping vs actual climbing. Maybe I'm just confused.
 
  • Like
Likes MasterTheStairs
  • #10
How much work is done depends on the user. If your body is kept at the same height (leg extending so your foot speed matches the speed of the stair moving down) there is less work done than if you "boost" yourself up with every step (center of mass moving up and down some). Your leg is still retracting and extending either way.

But all that may be misleading from an exercise point of view. For example, if you just squat down half way, say, and stay there then no work is being done (no movement), but your leg muscles will certainly be under tension and you will feel the strain shortly. You can get a great deal of exercise doing isometrics where nothing is moving so no work is being done.
 
  • Like
Likes MasterTheStairs
  • #11
OldYat47 said:
How much work is done depends on the user. If your body is kept at the same height (leg extending so your foot speed matches the speed of the stair moving down) there is less work done than if you "boost" yourself up with every step (center of mass moving up and down some). Your leg is still retracting and extending either way.
This is distracting from the point at hand and is contrary to the physics definition of work. Let us not complicate matters by having the fellow climbing the stairmaster perform different gyrations than the fellow climbing a flight of stairs.
 
  • Like
Likes MasterTheStairs and PeroK
  • #12
russ_watters said:
Yes.

Other than the links @anorlunda provided, the definition of work is the simplest way to explain it: work = force x distance. The fact that it is the treadmill/stairmaster that is "moving" and not the user doesn't matter as long as your foot applies the same force over the same distance.

Or if you really want to blow their minds, you can point out that "moving" is a relative thing. It is perfectly acceptable to declare the stairmaster/treadmill to be stationary and the person to be moving.

That's essentially the way I've always looked at it, but you put it more clearly than I normally ending up doing :smile: Perfect, thanks Russ.

Thanks very much for all the contributions, much appreciated and I have some new angles for explaining it to the doubters. It's surprisingly hard to find resources that explain basic principles like this as they apply to exercise, so I really appreciate you guys taking the time to answer.
 
  • Like
Likes russ_watters and PeroK
  • #13
PeroK said:
However, use of any external aids that are not moving down (e.g. the hand holds) does make a difference. To get the full value you mustn't pull on anything that is not descending. The people you see on the treadmill holding the bars, or pushing down on the handholds on the stairmaster are significantly reducing the work done.

Absolutely and this is a bugbear of mine in gyms. Usually it's more easily solved than the Stairmaster discussion, "Let go of that f$%&&^ing bar" normally sorts it out :smile:
 
  • #14
PeroK:
I'm still pondering. If I understand what you're saying:

I go to the mall and find the escalators. I walk up the 'down' escalator at a rate which just maintains my elevation.
I go to the 'up' escalator and climb it at the same step-pace as was established on the 'down' escalator. My elevation will increase 2x the rate of just 'riding' the escalator.
Your contention is that these will feel identical to the climber. Is that right?
 
  • #15
Dullard said:
PeroK:
I'm still pondering. If I understand what you're saying:

I go to the mall and find the escalators. I walk up the 'down' escalator at a rate which just maintains my elevation.
I go to the 'up' escalator and climb it at the same step-pace as was established on the 'down' escalator. My elevation will increase 2x the rate of just 'riding' the escalator.
Your contention is that these will feel identical to the climber. Is that right?
Nobody mentioned escalators. They aren't the same as stairs or stairmasters and the differences present themselves both with the mount/dismount and if you look at energy instead of power.
 
  • #16
Hmmmm. Ignore mount/dismount. I have no idea what you mean about energy and power - My simple understanding is that the former is the integral sum of the latter. How is a stairmaster different from walking up the down escalator? How is walking up the 'up' escalator not just like walking up stationary stairs?
 
  • #17
Dullard said:
How is a stairmaster different from walking up the down escalator? How is walking up the 'up' escalator not just like walking up stationary stairs?
Stairs have fixed lengths. Escalators have variable lengths depending on how they are used. Stairmasters have variable lengths depending on how they are used.

If you only care about power in the steady state, all are equal. But if you want to integrate over the length of the trip to find the energy expended, they can all be different.
 
  • #18
Dullard said:
PeroK:
I'm still pondering. If I understand what you're saying:

I go to the mall and find the escalators. I walk up the 'down' escalator at a rate which just maintains my elevation.
I go to the 'up' escalator and climb it at the same step-pace as was established on the 'down' escalator. My elevation will increase 2x the rate of just 'riding' the escalator.
Your contention is that these will feel identical to the climber. Is that right?

Yes, both of these cases will cause identical power output, energy expenditure, and perceived effort to the stair climber.
 
  • #19
The original post included a reasonably accurate (IMHO) description of stairmaster vs stairs. Namely, that the stairmaster provides exercise, but requires less effort than the 'equivalent' stairs. I felt no need to pipe up - I agree. Subsequent posts (Russ and PeroK) essentially claim that there is no difference between the stairmaster and the stairs. I do not agree with that for reasons previously stated. Post #17 is completely indecipherable (to me). The stairs in my house are Hickory.
 
  • #20
It isn't less effort though. It's identical, assuming you aren't bracing yourself on the handlebars or anything like that
 
  • Like
Likes .Scott, russ_watters and PeroK
  • #21
cjl said:
Yes, both of these cases will cause identical
cjl said:
It isn't less effort though. It's identical, assuming you aren't bracing yourself on the handlebars or anything like that
I don't agree. See post#5. A lot of money could be made betting on this.
 
  • #22
You don't agree that the escalator case is identical? It's a simple galilean transformation...
 
  • Like
Likes Tom Hammer
  • #23
Dullard said:
PeroK:
I'm still pondering. If I understand what you're saying:

I go to the mall and find the escalators. I walk up the 'down' escalator at a rate which just maintains my elevation.
I go to the 'up' escalator and climb it at the same step-pace as was established on the 'down' escalator. My elevation will increase 2x the rate of just 'riding' the escalator.
Your contention is that these will feel identical to the climber. Is that right?

Yes. Especially the case of walking up an up escalator. The effort must depend on your speed relative to the escalator. The speed of the escalator is irrelevant. And, in fact, the same applies to the down escalator.

If you wish to proceed with your mistaken analysis, you will have to relate the effort to the speed of the escalator. If you are walking up a down escalator does it get easier and easier the faster the escalator is moving down? If the escalator is moving down at 10m/s and you are running up the escalator at 5 m/s, is that easy? You're actually moving down at 5m/s, so how much work are you doing?

The only physically consistent answer is that the velocity of the escalator relative to the ground is irrelevant and only your speed relative to the escalator matters.
 
  • #24
I never claimed that my speed 'relative to the ground' mattered. See post # 5. I say that the 'F' in 'FdotdS' is larger for the case where I'm actually elevating my posterior in the gravity field (as opposed to just maintaining position). Or: you could go to the mall. We're talking about climber effort. If your analysis technique isn't centered on climber effort, it may produce incorrect results.
 
  • #25
cjl said:
Yes, both of these cases will cause identical power output, energy expenditure, and perceived effort to the stair climber.
Please be careful with that. The four scenarios are not fully defined. You are assuming the time and distance is the same in all cases, but that was not specified and of course the whole purpose of an escalator is to make them different.
 
  • #26
No. steady state.
 
  • #27
Dullard said:
The original post included a reasonably accurate (IMHO) description of stairmaster vs stairs. Namely, that the stairmaster provides exercise, but requires less effort than the 'equivalent' stairs. I felt no need to pipe up - I agree. Subsequent posts (Russ and PeroK) essentially claim that there is no difference between the stairmaster and the stairs.
You misread: The OP described why the power output is the same and everyone else agreed. There has been no dissension until/except you. So...
I do not agree with that for reasons previously stated.
[edit] Oh, post 5:
I believe that for the case of a treadmill/stairmaster, the effort is not trivial, but also not as large as the requirement for the equivalent fixed apparatus. Consider a user's leg (since that's what we're really talking about):
In the case of a fixed stair, the leg starts bent at the knee, the weight is shifted to that leg, and the entire body is elevated as the leg straightens. The leg 'sees' the weight of the body plus the force required to accelerate the body mass to the gravitationally superior position.

There is no acceleration. That's your error.
 
  • #28
russ_watters said:
Please be careful with that. The four scenarios are not fully defined. You are assuming the time and distance is the same in all cases, but that was not specified and of course the whole purpose of an escalator is to make them different.

I think it's introducing unnecessary pedantry to introduce different times, and given that the rates are identical, the distance is also identical (for the same time) relative to the escalator. It is less confusing to just state that the scenarios are identical, and from the perspective of the stair climber, they are.
 
  • Like
Likes russ_watters
  • #29
I'm going to try 1 more time. This is about effort required of the climber.

Stairmaster: the 'F' in 'FdotdS' is body weight (max). station-keeping.

Stairs: the F is body weight plus the force required to produce a net upward velocity. If the force were only body weight (or less), no 'climb' could occur. The add'l force is not trivial.

I don't know another way to explain it. If you disagree with me, don't bet your 401K on being right (you aren't) You might go to the mall, or talk to someone who has actually walked on a treadmill/stairmaster and compared.
 
  • #30
There is no force required for a net upward velocity beyond simply the weight of the stairclimber. Constant velocity requires the same force as no velocity.

To put this another way: If you were simply standing on the escalator but there was a scale between you and the stair, do you believe it would show your weight as higher on an upward traveling escalator than a downward one?
 
  • Like
Likes Asymptotic and Bandersnatch
  • #31
Dullard said:
If you disagree with me, don't bet your 401K on being right
Thread closed temporarily for Moderation...
 
  • #32
Dullard said:
I'm going to try 1 more time. This is about effort required of the climber.

Stairmaster: the 'F' in 'FdotdS' is body weight (max). station-keeping.

Stairs: the F is body weight plus the force required to produce a net upward velocity. If the force were only body weight (or less), no 'climb' could occur. The add'l force is not trivial.

I don't know another way to explain it. If you disagree with me, don't bet your 401K on being right (you aren't) You might go to the mall, or talk to someone who has actually walked on a treadmill/stairmaster and compared.

@Dullard -- Please lose the attitude, and please try to learn from the very valuable PF resource.

Thread reopened for now. Please respond in a substantive way to the helpful responses you have been provided so far. Thank you.
 
  • Like
Likes davenn
  • #33
Walking up the down escalator at a pace that leaves you in the same vertical location is identical to the mechanics of a stairmaster-type machine.
Referencing the original question, I stand by my previous post (#10). Any one user may get more or less benefit than any other user based on the way they use the machine. If a user boosts themselves up quickly at each step they will be doing more work because their center of mass will be moving up and down more (force X distance). Quickly extend the leg while the step is high, stand on step as it lowers until the next upper step is in place, quickly step and extend, etc. A user pacing at the same rate as the machine will do less work (center of mass in the same vertical location), but their legs are still moving so some work is being done. And for exercise "value", no motion is necessary at all (isometrics, yoga as examples).
 
  • Like
Likes sophiecentaur
  • #34
OldYat47 said:
Walking up the down escalator at a pace that leaves you in the same vertical location is identical to the mechanics of a stairmaster-type machine.
Referencing the original question, I stand by my previous post (#10). Any one user may get more or less benefit than any other user based on the way they use the machine. If a user boosts themselves up quickly at each step they will be doing more work because their center of mass will be moving up and down more (force X distance). Quickly extend the leg while the step is high, stand on step as it lowers until the next upper step is in place, quickly step and extend, etc. A user pacing at the same rate as the machine will do less work (center of mass in the same vertical location), but their legs are still moving so some work is being done. And for exercise "value", no motion is necessary at all (isometrics, yoga as examples).

... which is false. It doesn't matter whether you employ a funny walk, you cannot cheat gravity.
 
  • #35
OldYat47 said:
If a user boosts themselves up quickly at each step they will be doing more work because their center of mass will be moving up and down more (force X distance).
This is not correct.
 
  • #36
Dullard said:
I never claimed that my speed 'relative to the ground' mattered.
Then how do you define the following?
Dullard said:
... actually elevating...
Elevating in what frame of reference? Movement is frame dependent, and so is work.

Please read the other threads, before you keep repeating more wrong stuff that was already debunked there:
https://www.physicsforums.com/threads/fitness-treadmill-incline.937725/
https://www.physicsforums.com/threads/work-done-running-on-an-inclined-treadmill.927825/
 
  • #37
OldYat47 said:
...will do less work
See post above.
 
  • #38
OldYat47 said:
Referencing the original question, I stand by my previous post (#10). Any one user may get more or less benefit than any other user based on the way they use the machine.
In other words, if you change your gait it might get more or less efficient. This is both obvious and pointless as pertains to this thread.
 
  • #39
jbriggs444 said:
This is not correct.
Actually, it is true - with the caveat that it isn't very helpful to the thread, per my previous post...

Please note: the OP and the post quoted were about "exercise value", which is different than mechanical work. We've for the most part been assuming the motion is identical in the various cases, making the "exercise value" the same because the mechanical work done is the same.

But energy is *not* conserved in human motion. That means that smoother motions are more efficient than jerky motions because the extra acceleration energy of a jerky motion is not recovered when you decelerate again. So if you change your gait when using a machine you may expend more or less energy to do the same amount of mechanical work.
 
Last edited:
  • Like
Likes jbriggs444
  • #40
I've pondered some more. I apologize for getting the thread locked - I was smiling when I typed the offending words, but that apparently didn't come across.Is a treadmill/stairmaster as much ‘exercise’ as an equivalent ramp/stairs? I still don’t think so.

Case 1 (Treadmill)

Imagine a wheeled cart on an inclined (moving) treadmill. Neglect friction, etc. The cart is attached to the uphill end of the treadmill structure with a fixed rope – the rope is parallel to the deck of the treadmill. The tension (T) in that rope is a function of the incline angle and the weight of the cart; it is (exactly)the force required to maintain the cart position. The force does not change if the treadmill is stopped. It doesn’t change if the treadmill is reversed.

Case 2 (Ramp)

Move this rig to a stationary ramp of the same incline (or stay on the stopped treadmill). Note that the tension in the rope is exactly the same as in Case 1. The cart isn’t going up the ramp. You’ll need to ‘tug’ on the rope to get the cart moving and reel in the rope to maintain motion. The tension in the rope will (initially) be higher than ‘T’ while the cart accelerates from rest to climbing velocity; call that difference ‘F’. Once at climbing velocity, you’re back to ‘T.’ The application of the additional force (F) over the distance where velocity is changing is work that is not required in Case 1.

It is tempting to say that this is not steady-state behavior, and should be neglected for this and any similar analysis. In the example of the cart, I agree – there is no steady-state difference between a treadmill and a ramp. In the case of human locomotion, I have an apparently irreconcilable problem:

Any actual experiment comparing the amount of exertion required to walk on a treadmill/stairmaster with the effort required on their geometrically equivalent low-tech counterparts empirically demonstrates that they are not equivalent in terms of effort (it isn’t even very close). I’ve done it, and don’t know of anyone (who actually did an experiment) who disagrees.

Unless my understanding of the experimental data is wrong, I can only conclude:

The nature of human locomotion (the complexity of many parts moving different directions) requires that the penalty (‘F,’ above) is paid (at least in part) at every new step.

I suspect that the reason that the simple models don’t accurately answer the basic question is the inability of a human to ‘benefit’ from negative work. ‘Effort’ isn’t paid back on the other side of the hill. Work which would sum to zero in an over-simple model leaves a user sweating.
 
  • #41
Dullard said:
The nature of human locomotion (the complexity of many parts moving different directions) requires that the penalty (‘F,’ above) is paid (at least in part) at every new step.
You have not identified any difference in gait on the moving treadmill versus a stationary ramp that would be required to make F (the initial acceleration penalty) applicable.
 
  • Like
Likes russ_watters
  • #42
I don't believe that a difference in observable gait is required. The forces are different in the 2 cases, not (necessarily) the gait.
 
  • #43
Dullard said:
In the example of the cart, I agree – there is no steady-state difference between a treadmill and a ramp.
So we agree that there is no mechanical reason for the work to be different?

Dullard said:
I suspect that the reason that the simple models don’t accurately answer the basic question is the inability of a human to ‘benefit’ from negative work.
No, that is not the reason far any differences, because that inability exists in both cases.

What is different between treadmill and ground, are the visual cues (fixed vs moving surrounding) and the spatial limitations due to the size of the belt surface (no tolerance for variable walk speed). These can lead to a different gait pattern and muscle activation.

Dullard said:
The forces are different in the 2 cases, not (necessarily) the gait.

What forces are different despite same gait pattern and why?
 
  • #44
Dullard said:
I don't believe that a difference in observable gait is required. The forces are different in the 2 cases, not (necessarily) the gait.
Given identical gait, the forces are identical in the two cases.
 
  • Like
Likes russ_watters
  • #45
I think the posters are ignoring the very clear way @russ_watters delineated the problem in #39.
russ_watters said:
Please note: the OP and the post quoted were about "exercise value", which is different than mechanical work. We've for the most part been assuming the motion is identical in the various cases, making the "exercise value" the same because the mechanical work done is the same.

The question is not mechanical work, force*distance. It is human biological work, which obey the mechanical laws of physics but it also much more. Standing still consumes work in the body. We could say that mechanical work establishes the floor of biological work, but the average and peak values of biological work (exercise) are necessarily higher.

If everyone continues debating while thinking of differing definitions of work, the debate is endless. So please, let's stick to the OP's question about "exercise value" or biological work.
 
  • Like
Likes Tom.G and russ_watters
  • #46
anorlunda:
I agree. That's really at the heart of what I'm arguing. The 'net' work for the 2 cases is the same, but the ''peak-to-peak' is larger for actual climbing. My example with the cart was an attempt to illustrate that there are real differences in the forces.
 
  • #47
Dullard said:
The 'net' work for the 2 cases is the same, but the ''peak-to-peak' is larger for actual climbing.
Do you mean that there is more antagonist muscle co-contraction, which uses more energy, despite the same external work? This is theoretically possible, but why would it be more on ground?
 
  • #48
This is PF. We can do still better in making this a quality debate.

V02 https://en.wikipedia.org/wiki/VO2_max is a qualitative metric of exercise used by doctors. Rather than personal opinions, let's see some peer reviewed studies citing V02 for running, stairmasters, and treadmills. Or any other objective measures. But please let's stop with personal opinions unsubstantiated by references.

I would prefer to see this thread become better quality than to close it.
 
  • #49
Dullard said:
I don't believe that a difference in observable gait is required. The forces are different in the 2 cases, not (necessarily) the gait.
This is quite simply false. The force in both cases is exactly your weight.
 
  • #50
Dullard said:
anorlunda:
I agree. That's really at the heart of what I'm arguing. The 'net' work for the 2 cases is the same, but the ''peak-to-peak' is larger for actual climbing. My example with the cart was an attempt to illustrate that there are real differences in the forces.
Except that the cart example doesn't actually match the exercises. The cart example you gave is what happens if you hold on to the handlebars. We all agree that if you do that, it reduces or eliminates the exercise value.

Please: apply some numbers: A person weighs 170lb and walks smoothly up the stairs or stairmaster. What is the force applied?
Any actual experiment comparing the amount of exertion required to walk on a treadmill/stairmaster with the effort required on their geometrically equivalent low-tech counterparts empirically demonstrates that they are not equivalent in terms of effort (it isn’t even very close). I’ve done it, and don’t know of anyone (who actually did an experiment) who disagrees.
That is shocking to me. If there wasn't a significant exercise value, there would be no point to the exercise! Maybe you are using it wrong; are you holding on to the handlebars? I've seen people at the gym leaning hard on the Stairmaster handlebars.
 
Last edited:

Similar threads

Replies
8
Views
3K
Replies
5
Views
3K
Replies
5
Views
3K
Replies
49
Views
11K
Replies
4
Views
7K
Back
Top