- #1
EvLer
- 458
- 0
I think I sort of understand this but need confirmation/correction:
We have this formula in the book: X = P(b)X' (point = point-matrix * coord vector).
So the follow-up problem is this:
given basis X1 = [1, 0]t X2 = [1, 1]t what point X has b-coord vector X' = [-3, 2]t.
Well, it is straight-forward, by formula one gets X = [-1, 2]t.
So it looks to me that this point is with respect to the standard basis, am I correct?
We have this formula in the book: X = P(b)X' (point = point-matrix * coord vector).
So the follow-up problem is this:
given basis X1 = [1, 0]t X2 = [1, 1]t what point X has b-coord vector X' = [-3, 2]t.
Well, it is straight-forward, by formula one gets X = [-1, 2]t.
So it looks to me that this point is with respect to the standard basis, am I correct?