I think I sort of understand this but need confirmation/correction:(adsbygoogle = window.adsbygoogle || []).push({});

We have this formula in the book: X = P(b)X' (point = point-matrix * coord vector).

So the follow-up problem is this:

given basis X1 = [1, 0]t X2 = [1, 1]t what point X has b-coord vector X' = [-3, 2]t.

Well, it is straight-forward, by formula one gets X = [-1, 2]t.

So it looks to me that this point is with respect to the standard basis, am I correct?

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# Standard basis math

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