I think I sort of understand this but need confirmation/correction:(adsbygoogle = window.adsbygoogle || []).push({});

We have this formula in the book: X = P(b)X' (point = point-matrix * coord vector).

So the follow-up problem is this:

given basis X1 = [1, 0]t X2 = [1, 1]t what point X has b-coord vector X' = [-3, 2]t.

Well, it is straight-forward, by formula one gets X = [-1, 2]t.

So it looks to me that this point is with respect to the standard basis, am I correct?

**Physics Forums | Science Articles, Homework Help, Discussion**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Standard basis math

**Physics Forums | Science Articles, Homework Help, Discussion**