Standard Matrix of Linear Transformation T: R2--R2

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Homework Help Overview

The discussion revolves around finding the standard matrix of a linear transformation T: R2--R2 that switches the coordinates of points in the plane. Participants express confusion regarding the notation and the process of determining the matrix representation of the transformation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the implications of matrix multiplication and its linear properties, particularly how it relates to basis vectors. There are attempts to derive the matrix by applying the transformation to standard basis vectors and expressing the results in terms of matrix coefficients.

Discussion Status

The conversation is active, with several participants offering insights into how to approach the problem. Some guidance has been provided regarding the application of the transformation to basis vectors, and there is recognition of the relationship between the transformation and the matrix representation. However, there is no explicit consensus on the final matrix form yet.

Contextual Notes

Participants are navigating through notation issues and the requirements of the problem, indicating a need for clarity on how to represent the transformation in matrix form. There is an acknowledgment of the standard matrix and its role in the transformation process.

Derill03
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The question I am attempting to understand (my book absolutely sux) is this:

Give the standard matrix of the linear transformation T: R2--R2 which switches the two coordinates of every point?

Just not understanding what i am trying to accomplish here
 
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Sorry about the notation.

Find a,b,c,d such that


| a b |
| c d | < x, y> = <y, x>
 
Let us think about what matrix multiplication encodes. It is linear, so to understand what it does you just need to understand what it does to a basis (i.e. A(x+y)=Ax + Ay, so knowing what happens to x and y tells you what happens to x+y).

What happens if I multiply a matrix A into the column vector (1,0)^t? I get out the first column of A (check this!). Now find out what you get from multiplying into (0,1)^t

So if I know that A sends (1,0)^t to c and (0,1)^t to d, then I can write down A's matrix immediately.
 
Here is the simplest way to find the matrix of a linear tranformation, in a given basis.

Apply the transformation to the first basis vector: write the result in terms of the basis. The coefficients are the first column in the matrix.

Now do the same to the second basis vector. That gives the second column.

I notice, now, that this is exactly what matt grime said!

That is, write the matrix, as you do:
[tex]\begin{bmatrix}a & b \\ c & d\end{bmatrix}[/tex]
and apply it to [1 0].
[tex]\begin{bmatrix}a & b \\ c & d\end{bmatrix}\begin{bmatrix}1 \\ 0\end{bmatrix}= \begin{bmatrix}a \\ c\end{bmatrix}[/tex]
But since this transformation "swaps the two coordinates", [1 0] is taken to [0 1] so you must have [a c]= [0 1].
 
ok so my answer should be a 2x2 matrix?

I am to someway use the standard matrix
|1 0 |
|0 1 |
to get to my answer?

It seems that i should use the standard matrix muliplied by |0 1| to get a c, is this correct?
And then i could multiply standard matrix by |1 0| to get b d?
 
Of course the matrix of the transformation T is a 2 x 2 matrix. It maps a vector in R2 to a different vector in R2.

Look at HallsOfIvy's post; he has done half the problem for you.
 

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