Static equilibrium marbles problem

[krko]

Hey all, new member here

Homework Statement

Two uniform 75g marbles 2cm in diameter are stacked on top of each other in a container that is 3cm wide
the top marble touches right side of the container, the bottom touches the left side.
Point A is the bottom marble left contact point with the container, point B is the bottom marble touch the bottom of the container, point c is the top marble's contact point with the container

Attempt at a figure:
l top marble, point Cl
lmarble contact pointl
lpoint A, bottom marble l
l_____point B________l
What is the force the container exerts at point A,B, and C?
What force does each marble exert on each other?

Homework Equations

Basically since its static equilibrium, , all force and torques add up to zero. Also the equation for Torque, T=sin(phi)*lever arm

The Attempt at a Solution

force at B is easy to get since that's just the normal force equal to the combined weight of the two marbles.
At A and C, its obvious that they're equal. I can also get the torque due to the top marble on the bottome marble: weight*(.01m)*(sin(30)) after that I don't know what else to do.

 

[tiny-tim]

Welcome to PF!

Hey, krko ! Welcome to PF!

… I can also get the torque due to the top marble on the bottome marble: weight*(.01m)*(sin(30)) after that I don't know what else to do.

Is this frictionless?

You're taking moments about the point of contact between the marbles … why?

If you take moments (torques) about a point, you must do it for all the forces … that's why we usually choose a point about which some of the forces have zero moment.

Try again, taking moments about a different point.

 

[krko]

Okay, i uploaded an image of the problem. The torque I'm talking about is the torque caused by the top marble about point the center of the bottom marble. Although looking back i think I found my mistake, that I neglected the effect of the force of the container on point C on the bottom marble.