- #1

EEristavi

- 108

- 5

- Homework Statement
- A uniform pole is propped between the floor and the

ceiling of a room. The height of the room is 7.80 ft,

and the coefficient of static friction between the pole

and the ceiling is 0.576. The coefficient of static friction

between the pole and the floor is greater than that

between the pole and the ceiling. What is the length

of the longest pole that can be propped between the

floor and the ceiling

- Relevant Equations
- T = F R

I have a solution, However Cant understand 1 point.Now, This is the solution:

##N_2 l cos\theta + \frac 1 2 F_g l cos\theta - f_2 l sin\theta = 0##

## N_2(1 - \mu tan\theta) + \frac 1 2 F_g = 0##

This is the the

## N_2(1 - \mu tan\theta) < 0 ##

## (1 - \mu tan\theta) < 0 ##

##tan\theta > \mu^{-1} ##

##\theta ## ≅ 60.1

l = ##\frac h {sin\theta}##Can someone please explain it to me.

##N_2 l cos\theta + \frac 1 2 F_g l cos\theta - f_2 l sin\theta = 0##

## N_2(1 - \mu tan\theta) + \frac 1 2 F_g = 0##

This is the the

**point that I don't like**- yes it is less that 0, but it's even less that ##\frac 1 2 F_g = 0#### N_2(1 - \mu tan\theta) < 0 ##

**?**## (1 - \mu tan\theta) < 0 ##

##tan\theta > \mu^{-1} ##

##\theta ## ≅ 60.1

l = ##\frac h {sin\theta}##Can someone please explain it to me.