Static Equilibrium Problem: A diving board

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Homework Help Overview

The problem involves a diving board in static equilibrium, where a diver stands at one end while the board is supported at a point along its length. The discussion centers around calculating the force at the support point, taking into account the weights of both the diver and the board.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of torque equations to establish equilibrium, with one participant attempting to derive the force at the support point using torque calculations. Others question the distances used in the torque equations and seek clarification on how to determine the correct distances from the pivot point.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem and attempting to clarify the setup. Some guidance has been offered regarding the placement of weights and distances, but there is no explicit consensus on the correct approach yet.

Contextual Notes

Participants are navigating the complexities of static equilibrium and the specific distances involved in torque calculations, with some uncertainty about the correct application of these concepts in the context of the problem.

Chandasouk
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Homework Statement


A diving board of length L is supported at a point a distance x from the end, and a diver weighing w_1 stands at the free end . The diving board is of uniform cross section and weighs w_2.

yf_Figure_11_21.jpg


Find the force at the support point.

The Attempt at a Solution



I used the torque = 0 equation since this has to be an equilibrium, which also means the sum off all forces = 0 as well.

Net Torque=F_Support(x)-W_2(L/2)-W1(L-x) = 0

then

F_support = W_2(L/2)+W_1(L-x)/x

but that isn't correct
 
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The weight of the board acts at L/2 but that is not the distance from the pivot point.
 
How would I find that distance from the pivot point?
 
l/2 - x
 
I got to Find the force at the end that is held down as well

Would it be

Net Torque= -F_down(L)+W_2(x)-W1(L) = 0

F_down = w_2(x)-w1(L)/L

?
 

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