Static equilibrium and a diving board

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Homework Statement
A diving board of length 3.00 m is supported at a point 1.00 m from the end, and a diver weighing 500 N stands at the free end (Figure 1). The diving board is of uniform cross section and weighs 280 N.
Find the magnitude of the force at the support point and its direction.
Find the magnitude of the force at the left-hand end and its direction.
Relevant Equations
##\sum\tau=0##
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I take the left end as reference for torques:
$$\sum\tau=F_\text{support}+\frac 32\times280+3\times500=0\Leftrightarrow F_\text{support}=-192.\times10^1\,N$$
It's facing up.
I take the right end as reference for torques:
$$\sum\tau=-192.\times10^1\times2+\frac 32\times280+3F=0\Leftrightarrow F=114.\times10^1\,N$$
Its direction is downwards.
 
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It's correct, I entered the MAGNITUDE of the support force with a SIGN. Goodbye marks.
 
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