Static equilibrium; pulley and inclined plane problem.

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J-dizzal
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Homework Statement


What weight WB will cause the system to be in equilibrium? Neglect all friction, and state any other assumptions.
Diagram of a pulley system: block A of 175 lb on a 19° incline connected by cable over pulleys to a hanging pulley arrangement supporting block B weighted WB.

Homework Equations


ΣF=0

The Attempt at a Solution


I can't figure out what I am doing wrong with these pully problems, I tried putting in resultant forces at pully A, but that just added another variable.[/B]
Handwritten physics work with a sketch of a block on a 19 degree incline connected by pulleys to a hanging pulley system with block B, followed by equations for weight, F_x, and mass.
 
I did a redo of the tensions this time starting from A going to B, I am still missing something though. solving for weight at B i got 8.72lb (on the right side of my paper)
Handwritten physics solution on paper showing a block A on a 19 degree incline connected by pulleys to a hanging pulley system with block B, with tension labels T_A and T_B and force equations for static equilibrium.
 
Thyphon said:
It seems correct to me.
Yea, but I am still missing something, its not the correct answer.
 
Oh, find the F again you will see the wrong :) 79,5 N or kg ?
 
Thyphon said:
Oh, find the F again you will see the wrong :) 79,5 N or kg ?
If the weight of block A is 175 lb that is equal to 79.5N
 
ok i got, my mistake was trying to convert from english to standard, i should of just left it in english. thanks thypon.
 
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No, 1lb is equal to 0,453 kg, so 175lb =79,27 kg
N means kg*m/(s^2)
 
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Thyphon said:
No, 1lb is equal to 0,453 kg, so 175lb =79,27 kg
N means kg*m/(s^2)
i got confused because 175 lb of weight = 175 lb mass.
 
Thyphon said:
Is it okay now ?
yea its correct now. thanks