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Statically indeterminant problem

  1. Nov 28, 2007 #1

    I wonder if anyone can help/guide me with a problem i have, the figure below shows a free body diagram of a brake caliper, the force on the body acts at 30 degrees from the horizontal at point C, I resolved this to get the two forces shown in the x and y direction.

    http://www.volkstorque.co.uk/vt/imagehosting/676474d6a22acc4e.jpg [Broken]

    I have determined the values for v1 and v2 but i cannot decide how to get the values for h1 and h2, they cannot be the same due to the direction of the force. The problem appears to be statically indeterminant so is there another way i could solve this problem?
    Any suggestions appreciated
    Last edited by a moderator: May 3, 2017
  2. jcsd
  3. Nov 30, 2007 #2
    This probably should be placed in the homework help section. Your original resultant force appears to go through point A (ie. try summing moments about point A to start finding reactions).
  4. Nov 30, 2007 #3


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    You definitely have a situation where you'll need two equations to get the two unknowns. You can sum the B direction and sum moments about some point other than the three points on the triangle. You can't sum about A or B because that will eliminate H1 and H2. You can't sum about C because that eliminates the other forces.

    Is there anything with other boundary conditions that you could use to eliminate some variables?
  5. Nov 30, 2007 #4
    I summed moments about A and the resultant of the components shown doesn't go through point A so you can get V2 and therefore V1. I just solved the rest of it with what he gave assuming a RIGID BODY, using superposition and the geometry given. The additional equation is that H1=H2 for each superposition. I assumed the "brake caliper" is a solid, rigid triangle. The first time I did it
    I treated it like an open triangle truss but now I think the "brake caliper" is supposed to be a solid piece.
    Last edited: Dec 1, 2007
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