Statics Allowable load problem.

[kimann020]

Homework Statement

Determine allowable load on steel tube

L= 14 in
A= 11 in ^2
Es= 30 x10^6
θ=24,000 psi
δ= .008

Homework Equations

δ=PL/EA
θ=P/A

The Attempt at a Solution

.008=P(14 in)/(30 x 10^6)(11 in)^2

P=188571.4 lb


θ=P/A
24,000 psi=P/11 in^2

P=264,000?

My teach is telling me that the answer is P=2181.8 lbs i don't understand how or what i did wrong

 

[PhanthomJay]

I don't understand either if the load is axial tensile. Is it?