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Statics Allowable load problem.

  1. May 2, 2012 #1
    1. The problem statement, all variables and given/known data
    Determine allowable load on steel tube

    L= 14 in
    A= 11 in ^2
    Es= 30 x10^6
    θ=24,000 psi
    δ= .008



    2. Relevant equations
    δ=PL/EA
    θ=P/A


    3. The attempt at a solution

    .008=P(14 in)/(30 x 10^6)(11 in)^2

    P=188571.4 lb


    θ=P/A
    24,000 psi=P/11 in^2

    P=264,000?

    My teach is telling me that the answer is P=2181.8 lbs i dont understand how or what i did wrong
     
  2. jcsd
  3. May 2, 2012 #2

    PhanthomJay

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    I dont understand either if the load is axial tensile. Is it?
     
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