- #1

Blugga

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## Homework Statement

L=52 in

A=2.76 in^2

E=10.4*10^6 psi

## Homework Equations

σ=F/A

ε=σ/E

δ=εL

## The Attempt at a Solution

4) σ

_{AB}= (3P)/A

ε=(3P)/(AE)

δ

_{AB}=(3PL)/(6AE) → δ

_{AB}=(PL)/(2AE)

solving for P

P=[0.17*2*2.76*(10.4*10

^{6})]/52 → P=187680 lb → P=187.7 kip

5) Because AB and CD are in tension i did this...

σ

_{max}=σ

_{AB}+σ

_{CD}

σ

_{max}=[(-2P)/A]+[P/A]

solving for P and using 5000psi for σ

_{max}i get

P=-5000*2.76 → P=13800 lb → P=13.8kip

I tried looking for an example in the book to follow, but they were completely different. I hope i didn't mess up too bad.

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