1. The problem statement, all variables and given/known data L=52 in A=2.76 in^2 E=10.4*10^6 psi 2. Relevant equations σ=F/A ε=σ/E δ=εL 3. The attempt at a solution 4) σAB = (3P)/A ε=(3P)/(AE) δAB=(3PL)/(6AE) → δAB=(PL)/(2AE) solving for P P=[0.17*2*2.76*(10.4*106)]/52 → P=187680 lb → P=187.7 kip 5) Because AB and CD are in tension i did this... σmax=σAB+σCD σmax=[(-2P)/A]+[P/A] solving for P and using 5000psi for σmax i get P=-5000*2.76 → P=13800 lb → P=13.8kip I tried looking for an example in the book to follow, but they were completely different. I hope i didn't mess up too bad.