Thermal Switch Design Project fast

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naevitar77
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Homework Statement



There are three vertical metal strips (Steel, Aluminum, Steel) between two horizontal rigid bodies

alphaa = 12.5 E-6 /degF -- coefficient of thermal expansion
alphas = 6.6 E-6 /degF
Ea = 10 E6 psi -- Young's Modulus
Es = 30 E6 psi

The original dimensions of the switch are
ta = .0625 in -- thickness of aluminum
wa = .25 in -- width of aluminum
ts = .0625 in
ws = .125 in
L = 4 in -- length of all metals

With these dimensions, the switch will activate with a 180 degF temperature increase

By only changing the dimensions of the aluminum strip, I have to modify the switch to activate with 100 degF temperature increase

Homework Equations



δ = P*L/(E*A) + alpha*ΔT*L

Pcr = 4*pi^2*Ea*Ia / L^2 -- critical axial compressive load for the aluminum to buckle
Ia = wa*ta^3/12 -- minimum second moment of inertia

The Attempt at a Solution



I tried setting the deformation of the aluminum equal to that of the steel

δa = δs
Pa*L/(Ea*Aa) + alphaa*ΔT*L = Ps*L/(Es*As) + alphas*ΔT*L

from a free body diagram, I got Ps = -.5*Pa

Pa*L/(Ea*Aa) + alphaa*ΔT*L = -Pa*L/(2*Es*As) + alphas*ΔT*L
Pa*(1/(Ea*Aa) + 1/(2*Es*As)) = ΔT*(alphas - alphaa)

solving for Pa and simplifying using (1/a + 1/b)^-1 = ab/(a+b)

Pa = ΔT*(alphas - alphaa)*(2*Ea*Aa*Es*As / (Ea*Aa + 2*Es*As))

substituting Pcr = Pa

pi^2*Ea*wa*ta^3/(3*L^2) = ΔT*(alphas - alphaa)*(2*Ea*Aa*Es*As / (Ea*Aa + 2*Es*As))

now solving this for the temperature..

ΔT = pi^2*ta^2/(3*L^2) * (Ea*Aa + 2*Es*As)/(2*Es*As(alphas - alphaa))

when I plug in the variables for the 180 degF switch from above, I am getting
ΔT = -181.5 degF and I do not see anything wrong in my algebra; my units still come out to be degF.

Can someone tell me what I am doing wrong? Am I approaching this the right way?
 
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naevitar77: Excellent work, so far, except for one minor mistake. Pcr should be, Pcr = -4*Ea*Ia*(pi/L)^2. You erroneously omitted the negative sign here. Try it again.

By the way, numbers less than 1 should always have a zero before the decimal point. E.g., 0.25, not .25. See the international standard for writing units[/color] (ISO 31-0[/color]).
 
nvn said:
naevitar77: Excellent work, so far, except for one minor mistake. Pcr should be, Pcr = -4*Ea*Ia*(pi/L)^2. You erroneously omitted the negative sign here. Try it again.

The handout my professor passed out on this project defines Pcr without a negative sign. Why is it suppose to be negative?
 
Pcr is negative because it is compressive force. Your professor listed the magnitude.
 
That makes sense. Thank you so much nvn. You're a life saver!