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Chandasouk
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Determine the magnitude of the resultant moment produced by the forces about point O
Determine the direction of the resultant moment produced by the forces about point O
I first break the forces down to their components.
F1x = 500(4/5)
F1y=500(3/5)
F2x=600cos(60)
F2y=600sin(60)
The problem for me is when it comes time to add their moments. I am taking counter clockwise to be POSITIVE and clockwise to be NEGATIVE.
MF1x= -500(4/5)(0.25) = -100
MF1y= 500(3/5)(0.425) = 127.5
MF2x= -600cos(60) (0.25)=-75
MF2y= -600sin(60)(0.425) = -220.836478
so ƩM = -268.33 Nm turning clockwise?
The directions of the X components are confusing me, I would imagine they would cause the object to turn clockwise? I have only a few tries left on my HW so I just wanted to be sure of my answer.
Determine the magnitude of the resultant moment produced by the forces about point O
Determine the direction of the resultant moment produced by the forces about point O
I first break the forces down to their components.
F1x = 500(4/5)
F1y=500(3/5)
F2x=600cos(60)
F2y=600sin(60)
The problem for me is when it comes time to add their moments. I am taking counter clockwise to be POSITIVE and clockwise to be NEGATIVE.
MF1x= -500(4/5)(0.25) = -100
MF1y= 500(3/5)(0.425) = 127.5
MF2x= -600cos(60) (0.25)=-75
MF2y= -600sin(60)(0.425) = -220.836478
so ƩM = -268.33 Nm turning clockwise?
The directions of the X components are confusing me, I would imagine they would cause the object to turn clockwise? I have only a few tries left on my HW so I just wanted to be sure of my answer.
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