Statics: Reactions at rocker and pin on an A-shaped frame

Click For Summary
SUMMARY

The discussion focuses on determining the reactions at rocker support A and pin support B of an A-shaped frame using static equilibrium equations. The key equations utilized are ƩF = 0 and ƩM = 0, with specific calculations involving forces at angles, such as -Asin(25) and Acos(25). A critical insight emphasizes the importance of visualizing the problem geometrically to avoid errors in assumptions about reaction directions. This approach aids in sketching a triangle of forces, leading to a solution within 20% of the algebraically correct answer.

PREREQUISITES
  • Understanding of static equilibrium principles
  • Familiarity with vector components and trigonometric functions
  • Knowledge of force diagrams and free-body diagrams
  • Ability to apply equilibrium equations in mechanics
NEXT STEPS
  • Study the method of drawing free-body diagrams for complex structures
  • Learn about the geometric interpretation of forces in static systems
  • Explore advanced topics in static equilibrium, such as 3D force analysis
  • Investigate common mistakes in mechanics problems and how to avoid them
USEFUL FOR

Students in engineering mechanics, structural engineers, and anyone involved in analyzing static structures and forces.

JoeS4
Messages
7
Reaction score
0

Homework Statement



Determine the reactions at rocker support A and pin support B.

Homework Equations


ƩF = 0
ƩM = 0

The Attempt at a Solution



ƩFx = 0: -Asin(25) - (800lb) + Bx
ƩFy = 0: Acos(25) - (500lb) + By

I'm getting thrown off because of the rocker on an incline.
 

Attachments

  • IMG_0348.jpg
    IMG_0348.jpg
    33.4 KB · Views: 1,291
Last edited:
Physics news on Phys.org
You have made an assumption without declaring it about the direction of the reaction at B, and it contains an inconsistency. Before you apply equilibrium equations blindly, look at the problem geometrically so that you know the rough directions of the answers you seek. In this case, if you draw a line with a gradient 5 to 8 through E in the approximately south west direction, where does this line of the resultant applied force meet the direction of the reaction at A? Why is it that the reaction at B must also pass through this same point? What can you now conclude about the directions of the two reaction forces... and hence their components? Can you now sketch a triangle of forces and obtain an answer to the question within 20% of the algebraically "correct" answer. It is wise to do the rough thought process I have described, before doing the algebra. I concede that very systematic people can solve mechanics problems with no mental picture of it, but it is rare to do so without one or more errors. Looking at the problem geometrically is a form of error trapping.
 

Similar threads

  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 1 ·
Replies
1
Views
9K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 3 ·
Replies
3
Views
4K