Statistical thermodynamics: number of states of particle in central potential

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SUMMARY

The discussion focuses on calculating the number of states, denoted as \Phi(E), for a spinless particle with mass m in a central potential defined by V(\vec{r})=-\frac{a}{|\vec{r}|}. The Hamiltonian for this system is \mathcal{H}=\frac{p^2}{2m}-\frac{a}{r}, and the energy eigenvalues are expressed as E_n = -\frac{E_0}{n^2}, where E_0 represents the ground state energy. The key question raised is whether the number of states with energy less than a specified E<0 is infinite, indicating a need for clarity on the energy dependence of \Phi(E).

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  • Understanding of Hamiltonian mechanics
  • Familiarity with central potential problems in quantum mechanics
  • Knowledge of energy eigenvalues in quantum systems
  • Basic concepts of statistical thermodynamics
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Derivator
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Homework Statement


Give the number of states (energy of the state smaller than E<0) [tex]\Phi(E)[/tex] of a spinless particle with mass [tex]m[/tex] in the central potential [tex]V(\vec{r})=-\frac{a}{\left|\vec{r}\right|}[/tex].


Homework Equations





The Attempt at a Solution


Hi,

the hamiltonian of this problem is given by

[tex]\mathcal{H}=\frac{p^2}{2m}-\frac{a}{r}[/tex]
with [tex]|\vec{r}|=r[/tex]

I know, that the energy eigenvalues of such an potential can be expressed by:

[tex]E_n = -\frac{E_0}{n^2}[/tex]

where E_0 is the ground state energy.

But how do I count the number of states? Isn't the number of states that are smaller than a specific E<0 infinite?


derivator
 
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It is asking for the number of states [tex]\Phi(E)[/tex], so it seems to be energy dependent. I believe they want the number of states below the energy [tex]E[/tex].
 

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