Statistics of radioactive decay

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jdou86
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Homework Statement
GRE
Relevant Equations
GRE PHysics
Printed multiple-choice physics problem 16: a student's ten one-second radioactive decay counts (3, 0, 2, 1, 2, 4, 0, 1, 2, 5) and the question of how long to count for 1 percent uncertainty, options 80 s, 160 s, 2,000 s, 5,000 s, 6,400 s.
 
Same as in the other thread, you'll have to show what you did so far.
I extended the title to be more descriptive of the problem statement.

If you have a measurement, e.g. 100 counts in 7 seconds, what will your uncertainty on the rate be?
 
10 since since sigma is sqrt of N so I set sqrtN/N=0.1 but that didn't get me very far
 
jdou86 said:
but that didn't get me very far

These problems take longer than a second to solve. Why don't you write down your strategy for solving this. In words.
 
jdou86 said:
10 since since sigma is sqrt of N so I set sqrtN/N=0.1 but that didn't get me very far
Well, that is an important step already. An uncertainty of 10 is an uncertainty of 10% here. Too much, you'll need more counts to get to 1%...
 
Vanadium 50 said:
These problems take longer than a second to solve. Why don't you write down your strategy for solving this. In words.
I'm good thanks
 
mfb said:
Well, that is an important step already. An uncertainty of 10 is an uncertainty of 10% here. Too much, you'll need more counts to get to 1%...
Sorry it's supposed to be 0.01 but it still won't make sense because 10,000 counts represents 1000s measurement.
 
jdou86 said:
Sorry it's supposed to be 0.01 but it still won't make sense because 10,000 counts represents 1000s measurement.
My desperate attempt whcih matches the answer
 
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  • Handwritten blue-ink working on white paper: (4/100)^2 / (4π) = 4×10^-4; sample variance σ^2 = 2; √N/N = 0.01 so N = 10000; reduce 10/σ^2 × 1000 = 5000.
    IMG_20190903_013258.jpg
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10000 counts is correct. You can use the existing measurements to get a rough estimate of the decay rate and use that to get the time you need to accumulate 10000 counts.