I have the data set(adsbygoogle = window.adsbygoogle || []).push({});

# of freights - probability

1 - .075

1.5 - .025

2 - .425

2.5 - .150

3 - .125

3.5 - .100

4 - .050

5 - .025

6 - .025

The question is, what is the probability that at least 5 of 6 families purchased more than four freights.

I started with making a graph of the problem & found it was skewed right. With a mean 2.537 & standard deviation 1.002. So I've ruled out using normal distribution because its skewed right. The probability of purchasing more than four freights is .025+.025=.050. But is there a way to calculated the probability that 5 of 6 families purchased more than four?

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# Homework Help: Statistics, Probability Distribution

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