Statistics The gamma distribution

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Homework Help Overview

The discussion revolves around finding probabilities related to a random variable that follows a gamma distribution, specifically for two sets of parameters: (α = 2, β = 3) and (α = 3, β = 4). Participants are exploring how to approach the problem given the lack of a specific value for "x".

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants question the definition of the gamma distribution and its parameters, with some suggesting that the original poster (OP) should plug in the values to solve. Others express confusion about the absence of a specific "x" value needed for calculations.

Discussion Status

The discussion is ongoing, with participants providing guidance on the need for the incomplete gamma function or tables to compute probabilities. There is also mention of potential discrepancies in the representation of the gamma distribution across different sources, indicating a need for careful verification of definitions.

Contextual Notes

Participants note that the problem lacks specific information regarding "x" and highlight the importance of understanding the parameters used in the gamma distribution, as well as the potential for different conventions in its representation.

vanitymdl
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Homework Statement


Find the probabilities that the value of a random variable will exceed 4 if it has a gamma distribution with
(a) \alpha = 2 and \beta = 3
(b) \alpha = 3 and \beta = 4

3. The Attempt at a Solution [/b}
how would I even attempt this question?
 
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What is your definition of the gamma distribution? Is it defined with alpha and beta? If so, plug it in and solve.
 
The gamma distribution that is given includes an "x". How am supposed to solve for this equation when it doesn't give me an "X"
 
vanitymdl said:
The gamma distribution that is given includes an "x". How am supposed to solve for this equation when it doesn't give me an "X"

You need to have access to the incomplete gamma function (integral) or tables to compute the cumulative distribution function. Just be careful with the second parameter (\beta) as some tables/functions will use the reciprocal value here (eg 1/3 instead of 3).
 
$$
\frac{\beta^{\alpha}}{\Gamma(\alpha)}x^{\alpha - 1}e^{-\beta x}
$$
 
Dustinsfl said:
$$
\frac{\beta^{\alpha}}{\Gamma(\alpha)}x^{\alpha - 1}e^{-\beta x}
$$

I think the issue is that *some* sources give
\frac{1}{\beta^{\alpha}\: \Gamma(\alpha)} x^{\alpha -1} e^{-x/ \beta},
so the OP needs to check, not assume.

RGV
 

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