Steel ball floating due to surface tension?

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SUMMARY

The discussion focuses on determining the maximum diameter of steel and aluminum balls that can float on water due to surface tension at 20 degrees Celsius. The densities of steel (7800 kg/m³) and aluminum (2700 kg/m³) are provided for calculations. The key approach involves equating the gravitational force acting on the submerged portion of the ball to the surface tension force acting on the ball's circumference. The conclusion emphasizes that the maximum radius can be derived from these principles, with the understanding that if the radius exceeds a certain threshold, the ball will not float.

PREREQUISITES
  • Understanding of surface tension and its effects on floating objects
  • Knowledge of basic physics principles, particularly buoyancy and gravitational force
  • Familiarity with the equations for volume and density of spheres
  • Ability to perform calculations involving pressure and force
NEXT STEPS
  • Research the formula for calculating surface tension and its dependence on temperature
  • Learn about buoyancy principles and Archimedes' principle in fluid mechanics
  • Explore the effects of different materials on floating capabilities in water
  • Investigate the relationship between density and buoyancy for various shapes and sizes
USEFUL FOR

Students studying physics, particularly those focusing on fluid mechanics, as well as educators seeking to understand practical applications of surface tension and buoyancy in real-world scenarios.

magnusbarclay
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Hey!

Been doi some coursework from a text but can't seem to find any solutions so don't know if I am even remotely close to the right answer.

Q. A steel ball can float on water due to the surface tension effect.

a) Determine the maximum diameter of a steel ball that would float on water at 20 degrees.

b) What would be the maximum diameter for an aluminium ball.

Assume the densities of steel and aluminium to be 7800 kg/m^3 amd 2700 kg/m^3 respectively

I would appreciate working if possible. Thanks
 
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Could you use the standard template for homework help problems and give us what you think are the relevant equations and your attempt at a solution as well? You'll have a much better chance at getting a helpful response that way.
 
The object floating is a sphere, so you automatically know the radius of curvature of the interaction; it's the variable you're looking for. From this and the temperature of the water, you can get the surface tension, and pressure force on the ball.

You know the mass and the area the pressure acts on. The surface tension force must be greater than the gravitational force.
 
I have the very same problem:

-in order to maximize R, cos A must be 1; A=0 so that term can be left out in the eq
-in that case you have to make the assumption that you allow the ball to be half submerged.
-then the weight of metal = V(sphere) * g * p (density of metal) and let that equal to the surface tension s (N/m) acting on the equatorial circumference of the steel ball or 2*pi* R (ie set the force due to surface tension=weight of metal ball).
-solve for R and if you get anything a cm or more then you know this will not physically work
 
chamrul: you've answered the question correctly, but please don't provide detailed, step-by-step solutions to homework questions. We want to give the OP's a chance to think out problems by themselves.
 

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