Stopping a Baseball: Work, Force and Calculation

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SUMMARY

The discussion centers on calculating the work required to stop a baseball weighing 0.146 kg traveling at 40 m/s, which is determined to be 116.8 Joules. To find the average force needed to bring the ball to rest over a distance of 2 cm, the formula F_avg = W/d is applied, resulting in an average force of 5.48 kN. The calculations utilize the kinetic energy formula KE = (1/2)mv² to derive the necessary work. The final force calculation is confirmed through the equation w = F_avg * d.

PREREQUISITES
  • Understanding of kinetic energy calculations using KE = (1/2)mv²
  • Basic knowledge of work-energy principles in physics
  • Familiarity with force calculations and units (Newtons, Joules)
  • Ability to convert units, specifically between meters and centimeters
NEXT STEPS
  • Study the concept of work-energy theorem in physics
  • Learn about force calculations in different contexts, such as friction and acceleration
  • Explore the implications of stopping distances in sports physics
  • Investigate real-world applications of force and work in baseball dynamics
USEFUL FOR

Students studying physics, particularly those focusing on mechanics, as well as educators and coaches interested in the physics of sports and motion analysis.

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Homework Statement


Suppose a .146 kg baseball is traveling at 40 m/s.

a.How much work must be done on the ball to stop it? answer 116.8 J

b. if it is brought to rest in 2 cm what average force must act on the ball?

Homework Equations


KE=(1/2)mv^2

The Attempt at a Solution



w=Favg(.02m)
116.8=Favg (.02m)
Favg=116.8(N/m)/.02(m)

5840N/1000=5.48 kN
 
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