Strange physics question involving no constants and all variables.

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Homework Help Overview

The problem involves finding the functions for acceleration, velocity, and displacement as time-dependent variables, given the time derivative of acceleration represented by "K" and initial conditions. The task also includes demonstrating a relationship involving final and initial velocities and acceleration.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between displacement, velocity, and acceleration as functions of time. There are suggestions to consider derivatives and integrals to derive the functions a(t), v(t), and d(t). Some participants express uncertainty about the mathematical concepts involved, particularly regarding integration.

Discussion Status

The discussion is ongoing, with participants providing hints and guidance on how to approach the problem. There is a focus on understanding the connections between the different functions and the use of calculus concepts, although some participants indicate they have not yet covered certain topics in their coursework.

Contextual Notes

Some participants mention constraints related to their current level of calculus knowledge, indicating that they may need to seek additional resources to fully grasp the concepts being discussed.

TexasCow
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Homework Statement


"K" is the time derivative of acceleration. Assume initial conditions of Ao, Vo, and Do.("o"=initial).

Find:
a(t):
v(t):
d(t):

Show that:
af^2=ao^2+2J(Vf-Vo)


Homework Equations



I'm honestly lost on this one..I don't know where to start. I could probably do it with numbers but clueless with variables!



The Attempt at a Solution

 
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Hey,

Remember that what is common between the: displacement, velocity, and acceleration functions; are that they're all functions of time, indicating that t is your only variable.

Therefore, consider the following,

<br /> {\frac{d}{dt}}{\left[a(t)\right]} = K<br />

So, if the derivative with respect to t was taken to get K, how do you get back a(t)?

Once you figure that out repeat for v(t) and d(t).

Thanks,

-PFStudent
 
Last edited:
Hint: Use the Fundamental Theorem of Calculus.
 
Integral maybe?
 
TexasCow said:
Integral maybe?

Hey,

Yes. To get you started here is how it looks,

<br /> {a(t)} = {\int_{}^{}}{K}{dt}<br />

Thanks,

-PFStudent
 
Well we haven't gotten there in calc yet but I'm sure I can find out how to do that online somewhere.
 
Hint 1: K is the same as K^1
Hint 2: a(t) = K^2/2 + C
 

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