Streamlines from strain rate tensor

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SUMMARY

The discussion centers on the relationship between strain rate tensors and the ability to sketch streamlines in fluid dynamics. It establishes that while the strain rate tensor can provide insights into the kinematic properties of fluids, it is insufficient for determining flow direction without the velocity vector. The conversation also clarifies that in 3D potential flows, streamlines are not confined to a single plane but are influenced by the gradient of the potential function, which is orthogonal to the level surfaces. Additionally, it emphasizes that the strain rate tensor does not account for the antisymmetric part of the velocity gradient tensor, which is essential for understanding fluid rotation.

PREREQUISITES
  • Understanding of strain rate tensors in fluid mechanics
  • Familiarity with velocity fields and their components (u, v, w)
  • Knowledge of potential flow theory and scalar potential functions
  • Basic concepts of eigenvalue problems in linear algebra
NEXT STEPS
  • Study the relationship between strain rate tensors and velocity gradient tensors
  • Explore the implications of potential flow theory in three dimensions
  • Learn about the role of vorticity in fluid dynamics
  • Investigate methods for visualizing flow fields from velocity data
USEFUL FOR

Fluid dynamics researchers, mechanical engineers, and students studying kinematics and fluid mechanics will benefit from this discussion, particularly those interested in the mathematical modeling of fluid flow and the application of strain rate tensors.

vktsn0303
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I was reading about strain rate tensors and other kinematic properties of fluids that can be obtained if we know the velocity field V = (u, v, w). It got me wondering if I can sketch streamlines if I have the strain rate tensor with me to start with. Let's say I have the strain rate tensor:

eq0073SP.gif


Would it now be possible to sketch the flow field and determine the flow direction from this? If yes, how?

Also, in 2D potential flows streamlines are perpendicular to potential lines. Does this mean in 3D the set of streamlines will be a plane with a line perpendicular to it? And can this also be explained with just the help of the strain rate tensor above by solving an eigenvalue problem?
 
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No. The strain rate tensor can be zero while maintaining a steady flow. Think a body of fluid in uniform translation and rotation.

vktsn0303 said:
Also, in 2D potential flows streamlines are perpendicular to potential lines. Does this mean in 3D the set of streamlines will be a plane with a line perpendicular to it?

For a potential flow ##\vec v = \nabla \phi## for some ##\phi##. The gradient is always orthogonal to the level surfaces of a scalar function. The streamlines for an irrotational flow will therefore always be perpendicular to the potential surfaces.
 
vktsn0303 said:
I was reading about strain rate tensors and other kinematic properties of fluids that can be obtained if we know the velocity field V = (u, v, w). It got me wondering if I can sketch streamlines if I have the strain rate tensor with me to start with. Let's say I have the strain rate tensor:

View attachment 204609

Would it now be possible to sketch the flow field and determine the flow direction from this? If yes, how?

Also, in 2D potential flows streamlines are perpendicular to potential lines. Does this mean in 3D the set of streamlines will be a plane with a line perpendicular to it? And can this also be explained with just the help of the strain rate tensor above by solving an eigenvalue problem?
No. Aside from not knowing the velocity vector at any given location (which would provide the constant of integration), the strain rate tensor represents only the symmetric part of the velocity gradient tensor, and does not include the antisymmetric part (i.e., the vorticity tensor) which describes rotation of the fluid parcels.
 

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