Struggling with Fourier Transform in Math Methods Class

Click For Summary
The discussion revolves around a student's difficulties with Fourier Transforms in a math methods class, particularly without prior knowledge of differential equations. The student understands the concept but struggles with specific elements of the problem, especially regarding the Dirac delta function and its properties. They explore the relationship between the delta function and the Heaviside step function, suggesting that understanding these could help resolve their issues. The conversation hints at the importance of absolute values in the solution and the potential connection to the Heaviside function. Overall, the student seeks clarity on these mathematical concepts to improve their understanding and solve the problem effectively.
rdfloyd
Messages
29
Reaction score
0
I haven't had differential equations yet, so I am struggling in your math methods class. I understand what a Fourier Transform is, but I'm having trouble with this particular problem.

Homework Statement


Here's a screenshot. Better than I can write it.

http://i.imgur.com/PQ6tB.png

The Attempt at a Solution



Here's what I did:

http://i.imgur.com/JuUzu.jpg

The capital letters have already been transformed, so if I take the inverse transformation, I should end up with what I had to begin with.

Where I get stuck is with the Q, \frac{1}{D}, \frac{1}{(w^{2}+k^{2})}. Is it possible to split the \Delta[w] up from the fraction, because that would just be back to \delta[x].

If I'm completely wrong and beyond hope, just tell me and I will go cry in a corner.

Thanks!
 
Last edited:
Physics news on Phys.org
Oh hey, I think the issue may be that ##\delta[x]## is actually the dirac delta function, which has the property that
$$
\int_{-\infty}^\infty f(x)\delta(x)\, \mathrm{d}x = f(0)
$$
This would mean that
$$
\mathbb{F}[Q\delta(x)]=Q
$$
See if this fixes things. I tried the problem and still had a good deal of trouble with it :confused:, but you may be able to swing the rest from there.

PS: I'd be interested to see the rest of your solution when you get it. I suspect it may have to do with absolute values and or the step function.
 
Using what you said (which makes sense; can't believe I didn't see that), I got this:

http://i.imgur.com/lBkuj.jpg

There were absolute values, however, I omitted them because I didn't think they were necessary.
 
Hmmm...
You know how ##|x|## has slope -1 until ##x=0##, and then it has slope 1? I think you might be able to make this claim:
$$
\frac{\mathrm{d}|x|}{\mathrm{d}x}=2\mathbb{H}(x)-1\text{, where H is the Heaviside step function. Note also that}\\
\frac{\mathrm{d}\mathbb{H}}{\mathrm{d}x}=\delta(x)
$$
I have a suspicion this might be somehow related. I still haven't figured it out, but now it's starting to bother me.
 
That's the first time I've heard of the Heaviside. What are it's uses (not only to this problem)?
 
I don't know! In fact, I don't even know why or where I heard of it! But check this page out, it's pretty cool: http://mathworld.wolfram.com/HeavisideStepFunction.html
I guess if you wanted to, you could also represent the T=0 Fermi distribution using the Heaviside... Not sure that would actually be useful, though.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

Similar threads

  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
8
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K