Flucky
- 93
- 1
Hi all sorry the title couldn't be more descriptive.
I'm having a bit of a brain block with this equation (it's the very end of a problem).
N(\frac{5}{6})^{N-1} > \frac{27}{5}
My line of thought was to get the first N in terms of the power N-1..
How do I find N?
I'm having a bit of a brain block with this equation (it's the very end of a problem).
N(\frac{5}{6})^{N-1} > \frac{27}{5}
My line of thought was to get the first N in terms of the power N-1..
How do I find N?