MHB Stuck with probability question involving tree diagram?

AI Thread Summary
The discussion centers on a probability question involving a golfer named Suzi who randomly selects from five clubs, with given probabilities for good and bad shots depending on whether she chooses the right or wrong club. Participants clarify that the probability of selecting the right club is 1/2, as she chooses randomly. To solve for the probability of reaching the green in at most two shots, it's suggested to calculate the complement of both shots being bad and subtract that from 1. There is some debate about the correct probabilities for the right and wrong clubs, with differing opinions on how to approach the problem. The conversation emphasizes the importance of accurately constructing the tree diagram and understanding the underlying probabilities.
tantrik
Messages
13
Reaction score
0
Dear friends,

I'm unable to solve the following probability question. Please help me solve it. Thanks in advance. The answer given in the book is: 5/9 [for part (b)]. Don't know even if the answer is correct.

Suzi has taken up golf, and she buys a golf bag containing five different clubs. Unfortunately she does not know when to use each club, and so chooses them randomly for each shot. The probabilities for each shot that Suzi makes are shown below

Right club
--------------
Good shot - 2/3
Bad shot - 1/3

Wrong club
-----------------
Good shot - 1/4
Bad shot - 3/4

a) Use the above information to construct a tree diagram.
b) At one short hole, she can reach the green in one shot if it is 'good'. If her first shot is 'bad', it takes one more 'good' shot to reach the green. Find the probability that she reaches the green in at most two shots.


I drew the tree diagram given below. Don't know whether it is correct or not. Problem is what would be the values for P(right club) and P(wrong club). Still I don't know which outcomes should I take for finding the solution to part (b). Let me know what to do next.View attachment 5996
 

Attachments

  • Tree diagram for part (a).jpg
    Tree diagram for part (a).jpg
    20.9 KB · Views: 119
Mathematics news on Phys.org
tantrik said:
Dear friends,

I'm unable to solve the following probability question. Please help me solve it. Thanks in advance. The answer given in the book is: 5/9 [for part (b)]. Don't know even if the answer is correct.

Suzi has taken up golf, and she buys a golf bag containing five different clubs. Unfortunately she does not know when to use each club, and so chooses them randomly for each shot. The probabilities for each shot that Suzi makes are shown below

Right club
--------------
Good shot - 2/3
Bad shot - 1/3

Wrong club
-----------------
Good shot - 1/4
Bad shot - 3/4

a) Use the above information to construct a tree diagram.
b) At one short hole, she can reach the green in one shot if it is 'good'. If her first shot is 'bad', it takes one more 'good' shot to reach the green. Find the probability that she reaches the green in at most two shots.


I drew the tree diagram given below. Don't know whether it is correct or not. Problem is what would be the values for P(right club) and P(wrong club). Still I don't know which outcomes should I take for finding the solution to part (b). Let me know what to do next.

Hi tantrik! Welcome to MHB! ;)

You're tree diagram is fine for part b (for part a we shouldn't have the last level).

The values for 'right club' and 'wrong club' follow from "Unfortunately she does not know when to use each club, and so chooses them randomly for each shot".
It means 50-50.
That is, P(right club) = 1/2.

To solve part b, we need to sum the probabilities where at least one shot is good.
Or alternatively, which is easier, sum the probabilities where both shots are bad (the complement), and subtract it from 1.
 
I believe (trembling with terror) that I like Serena is wrong. Since there are 5 clubs and Suzi chooses the club for each shot at random, then (assuming there is exactly one club that is "right" for each shot), the probability Suzi chooses the right club is 1/5, the probability Suzi chooses the wrong club is 4/5.
 
I agree with HallsofIvy.
Oh, and sorry for coming down a bit hard last time round.
 
Suppose ,instead of the usual x,y coordinate system with an I basis vector along the x -axis and a corresponding j basis vector along the y-axis we instead have a different pair of basis vectors ,call them e and f along their respective axes. I have seen that this is an important subject in maths My question is what physical applications does such a model apply to? I am asking here because I have devoted quite a lot of time in the past to understanding convectors and the dual...
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Back
Top