Students to classrom heat transfer

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SUMMARY

The heat transfer from 90 students to a classroom over 50 minutes results in a total energy input of 27,000,000 Joules. Given the classroom volume of 3200 cubic meters, with air having a thermal capacity of 1020 J/kgK and a density of 1.20 kg/m3, the temperature increase can be calculated using the formula Q = mcΔT. The mass of the air in the classroom is 3840 kg, leading to a definitive temperature rise based on the total heat input.

PREREQUISITES
  • Understanding of basic thermodynamics principles
  • Familiarity with the concepts of heat transfer and thermal capacity
  • Knowledge of the formula Q = mcΔT
  • Basic calculations involving energy, mass, and temperature
NEXT STEPS
  • Calculate the temperature increase using Q = mcΔT with the provided values
  • Research the effects of heat transfer in closed systems
  • Explore the implications of ventilation on classroom temperature control
  • Learn about thermal properties of air and their impact on indoor environments
USEFUL FOR

Students in physics or engineering, educators involved in classroom management, and anyone interested in the principles of heat transfer and thermal dynamics in enclosed spaces.

snabelpablo
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A student produces heat with a rate of 100W. How much heat is transferred from 90 students to a classroom in 50 minutes?

Attempt at solution:
100W (100 J/s) * 90 students * 3000 seconds = 2,7 * 10^7 J. Does this make sense?

The classroom is 3200 cubic meters and the air in it has a thermal capacity of 1020 J/kgK and a density of 1.20 kg/m3. If no heat escapes from the room and the ventilation is broken, how much does the air temperature increase during the 50 minutes?

Attempt at solution:
None. Some help, please?
 
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The number of Joules transferred is correct. Do you know of an expression that relates the change in temperature to the heat input?
 

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