Force & Acceleration: Explaining F=ma in Disguise

  • Thread starter Thread starter 404
  • Start date Start date
  • Tags Tags
    Stupid
Click For Summary
SUMMARY

The discussion centers on the relationship between force and acceleration as expressed in the equation F=ma, derived from a force vs. acceleration graph. In this context, force is represented as the dependent variable (Y), acceleration as the independent variable (X), and mass as the slope (m) of the linear equation. The teacher's emphasis on avoiding the use of X and Y suggests a focus on understanding the underlying relationships rather than the conventional graphing terminology. The conclusion drawn is that the linear relationship indicates that force is directly proportional to acceleration, scaled by mass.

PREREQUISITES
  • Understanding of Newton's Second Law of Motion
  • Familiarity with linear equations and graphing concepts
  • Knowledge of dependent and independent variables
  • Basic grasp of slope-intercept form (y=mx+b)
NEXT STEPS
  • Study the implications of Newton's Second Law in various physical scenarios
  • Explore graphical representations of linear relationships in physics
  • Learn about the concept of proportionality in physics
  • Investigate the role of mass in dynamics and its effect on acceleration
USEFUL FOR

Students studying physics, educators teaching Newtonian mechanics, and anyone interested in the mathematical representation of physical laws.

404
Messages
52
Reaction score
0
Ok we did a force vs acceleration graph in class, and got an equation from it(couldnt use Y and X for the equation). The question is explain why the equation is F=ma in disguise. Obviously it is, like force is the y, slope is the mass etc, but how can I actually explain it is?
 
Physics news on Phys.org
So force is your y, acceleration is x, and mass is the slope. Do you know the relationship found in the graph that relates to the axes and slope?
 
For a linear equation y=mx+b...

Here we are neglecting b, the y-intercept. What does that leave us?
 
But the teacher said we couldn't use X and Y...
 
I don't understand what he/she wants from you. How are you supposed to explain the relationship between variables on a linear graph without using x and y??

The only way I can see how is to generalize and say that basically a linear graph has these relationships with the axes and slope... but without mentioning the axes that will be a bit vague.
 
The acceleration is the indep. variable, the force is the dep variable. They have a directly proportional relationship by a scalar quantity 'm'
 
may be what your teacher wants is to show that
Y=F (force)
X=a (acceleration)
m(gradient)=m(mass)
 
Alight I got it now, thanks.
 

Similar threads

  • · Replies 30 ·
2
Replies
30
Views
4K
Replies
11
Views
1K
Replies
44
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
7
Views
1K
  • · Replies 6 ·
Replies
6
Views
5K
  • · Replies 2 ·
Replies
2
Views
3K