Lee Messages 55 Reaction score 0 Thread starter Nov 12, 2006 #1 Which substituation would I need to use for this intergral; [y.du/(y^2 + (x - u)^2)]
Galileo Science Advisor Homework Helper Messages 1,980 Reaction score 7 Nov 12, 2006 #2 The integrand looks like [tex]1/(1+x^2)[/tex] which has antiderivative arctan(x). Try to make substitutions to match that expression.
The integrand looks like [tex]1/(1+x^2)[/tex] which has antiderivative arctan(x). Try to make substitutions to match that expression.
Lee Messages 55 Reaction score 0 Nov 13, 2006 #3 Got it, take the y out the intergral, make b=x-u then db=-du sub in and use the arctan intergral, getting -tan^-1((x-u)/y)
Got it, take the y out the intergral, make b=x-u then db=-du sub in and use the arctan intergral, getting -tan^-1((x-u)/y)