Substituting for Intergral: Tricky Intergral

  • Thread starter Thread starter Lee
  • Start date Start date
Click For Summary
SUMMARY

The discussion focuses on the substitution method for the integral of the function y.du/(y^2 + (x - u)^2). The integrand resembles the form 1/(1+x^2), which has the antiderivative arctan(x). The recommended substitution involves taking y out of the integral and setting b = x - u, leading to db = -du. This results in the final expression of -tan-1((x-u)/y) as the solution.

PREREQUISITES
  • Understanding of integral calculus
  • Familiarity with substitution methods in integration
  • Knowledge of the arctangent function and its properties
  • Experience with variable transformations in integrals
NEXT STEPS
  • Study advanced techniques in integral calculus
  • Learn about variable substitution in definite integrals
  • Explore the properties and applications of the arctangent function
  • Practice solving integrals involving trigonometric substitutions
USEFUL FOR

Students and professionals in mathematics, particularly those focusing on calculus and integral techniques, as well as educators teaching integration methods.

Lee
Messages
55
Reaction score
0
Which substituation would I need to use for this intergral;

[y.du/(y^2 + (x - u)^2)]
 
Physics news on Phys.org
The integrand looks like [tex]1/(1+x^2)[/tex] which has antiderivative arctan(x). Try to make substitutions to match that expression.
 
Got it, take the y out the intergral, make b=x-u then db=-du sub in and use the arctan intergral, getting -tan^-1((x-u)/y)
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 7 ·
Replies
7
Views
1K
Replies
3
Views
2K
  • · Replies 10 ·
Replies
10
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
23K
Replies
3
Views
2K