1. May 27, 2008 #1

   temaire

   

   1. The problem statement, all variables and given/known data
   [tex]\int2e^-^7^xdx[/tex]
   
   
   2. Relevant equations
   None
   
   
   3. The attempt at a solution
   
   [tex](\frac{-2}{7})(\frac{e^-^7^x}{-7})+C[/tex]
   
   
   This is as far as I can go, but the answer is:
   
   [tex]\frac{-2e^-^7^x}{7}+C[/tex]

    

   temaire, May 27, 2008
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3. May 27, 2008 #2

   rocomath

   

   How did you get two 1/7 terms?

    

   rocomath, May 27, 2008
4. May 27, 2008 #3

   temaire

   

   I took the antiderivative of [tex]e^-^7^x[/tex].

    

   temaire, May 27, 2008
5. May 27, 2008 #4

   rocomath

   

   So, why do you have 1/7 * 1/7? Just do it again from scratch and you'll probably see what you did wrong.

    

   rocomath, May 27, 2008
6. May 27, 2008 #5

   rocomath

   

   [tex]2\int e^{-7x}dx[/tex]
   
   [tex]-\frac 2 7\int -7e^{-7x}dx[/tex]
   
   You don't need to divide by another -7. It's already in standard form!

    

   rocomath, May 27, 2008
7. May 27, 2008 #6

   temaire

   

   I've got it now, thanks.

    

   temaire, May 27, 2008

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