Sum of Angle A and B: Does Proportion Matter?

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Homework Help Overview

The discussion revolves around the geometric proof involving the sum of angles A and B, particularly in the context of triangles and their leg proportions. Participants are examining the validity of substituting one triangle for another in the proof, questioning whether the differing leg ratios affect the outcome.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants are exploring the implications of substituting triangles in a proof, questioning the relevance of leg proportions. Some express understanding of angle relationships but are uncertain about the validity of using different triangles with potentially different ratios.

Discussion Status

The discussion is active, with participants providing insights and clarifications. Some have offered guidance on the geometric relationships involved, while others are still seeking clarity on specific aspects of the proof and the triangles involved.

Contextual Notes

There is mention of a missing right triangle in the diagrams, which may affect the understanding of the proof. Participants are also navigating the complexities of angle relationships and triangle properties without reaching a definitive consensus.

Miike012
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Ok.. I've been looking at the sum of angle A and angle B...
in the proof they substituted angle A ( adjacent to angle B ) for the upper right angle A.
It seems obvious that one can do this because they are the same exact angle, but what is confusing me is that the triangles do not have the same exact leg proportions... Does that not matter?
 

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It has to do with the geometric proof of a line intersecting two parallels. Notice that the central line in the middle shows two right angles, so you know they are parallel.

More specifically:

zn8wfp.jpg


Hope that is what you were asking? It was a bit unclear.
 
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I totally understand how they got the angles however I don't understand how they could exchange the triangle that I highlited in yellow for the triangle that I highlighted in orange... because after all when we use sine.. cos... tan... ect.. we are trying to find the leg ratios of a triangle... but if we use the smaller triangle that I highlited in orange.. it won't have the same ratio as the one in yellow..
The only way that I understand how they can use it is because it looks like they are multiplying by a factor of one.. so it wouldn't change the result...
 
I don't see any of the triangles highlighted? Could you re-upload the picture perhaps.
 
sorry... here it is..
 

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I see what you are trying to do. Is this the proof for sin(a+b) ? If so, then your diagram is missing a right triangle. The hyp of both yellow and orange triangles should be perpendicular (because the hyp of the orange triangle is supposed to represent the sine of angle B). Knowing that, we can determine that the bottom right angle of the orange triangle is equal to (90-a). The top angle a is unknown for now, we will call it x. The remaining angle is 90. The sum of all three angles must be 180, so we can write an equation such as:

90 + x + (90-a) = 180
180 + x - a = 180
x - a = 180 - 180
x - a = 0

In order for x-a to equal zero, x must be a.
 

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