Sum of energy in a system like barometer

In summary: But if the thing is 10m high the pressure at the top will be close to a vacuum so work has to be done on the object to get it out to atmospheric pressure. So I agree. But I think it's not possible, where the energy is lost ?
  • #1
lba
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0
The drawing show a barometer with water inside. If I move up object with air inside I recover PV energy (P=external pressure, V=volume of object). If I want to move out object when it is at top, I need PV, is that ?

So if it's that. If I replace:

1/ gravity by balls attracted with springs (for have law of gravity in blue column)
2/ atoms with empty balls with very thin walls
3/ pressure with velocity of empty balls
4/ object to move up with some empty balls

I can disappear empty balls at top: at top we can recover energy from velocity and let at top only the small walls of balls. If walls are very very thin, I let virtually nothing. With friction = 0 where the energy is lost ?
 

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  • #2
It takes energy to force the object into the bottom of the tube against 10m head of water (about 1 bar).

I'd be surprised if the idea wasn't in the museum somewhere..

http://www.lhup.edu/~dsimanek/museum/unwork.htm

Oh look it is..

http://www.lhup.edu/~dsimanek/museum/unwork.htm#buoy4

It appeared in the June 1825 issue of The Mechanic's Magazine

The work required to push a ball into the bottom of the tube by any method requires that work be done against the pressure difference between inside and outside. This is (at least) as large as the work the ball does in rising to the top of the tube.
 
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  • #3
thanks for your reply :)

but it's like a barometer not a simple column of water, no need energy to enter in water because outside pressure = 1 bar.
 
  • #4
That just means the problem is elsewhere. If the thing is 10m high the pressure at the top will be close to a vacuum so work has to be done on the object to get it out to atmospheric pressure.

Personally I don't find it productive looking for reasons why a perpetual motion machine won't work.
 
  • #5
If the thing is 10m high the pressure at the top will be close to a vacuum so work has to be done on the object to get it out to atmospheric pressure.
I'm agree with that, the sum of energy is 0.

But I would like to know with a macroscopic scale system. Imagine the system with balls, velocity, springs, ..., like that it's possible to recover energy from velocity. And if balls are empty, they disappear at top, let only walls and walls can be very small in theory.
 
  • #6
I put a drawing for show an example. Sure the system would be complex but it's only a technological problem.
 

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  • #7
I'm not sure what you are trying to achieve? It's easy to make a system that appears to have a cycle over which the energy sums to zero. Here are three examples..

1) Planets orbiting the sun. PE and KE exchanged in eliptical orbits.

2) Magnetic spring..Imagine three magnets arranged...

NS SN NS

with the outer pair fixed to the desk and the middle one free to slide left and right. If you pull it to the left and let go it will oscillate back and forth.

3) Imagine a mass on a spring. If you press the mass down energy is stored in the spring. Let it go and that stored energy is converted to PE. The mass bounces up and down.

In an ideal world the these systems keep going forever because the energy sums to zero. How well they work in practice is also "only a technological problem".

There is no excess energy to be harvested from the velocity the objects have in your system. That energy will have come from somewhere.

After awhile most people stop playing noughts and crosses (aka Tic Tac Toe) because they realize you can only ever draw no matter how well you play.
 
  • #8
I'm trying to understand where energy is lost. First, with a system with water+gravity+vacuum+pressure (a barometer), the sum of energy is 0, we agree with that. Now, take the hypothesis we can recover energy from temperature without lost energy. With a barometer when you put a ball with air inside at bottom (air come from atoms around), when the ball move up in water, we recover energy PV (p=external pressure and V=volume of ball). At top, recover energy Wth from temperature. And put atoms of balls outside (small volume because it's a liquid). Move out atoms of ball and give the energy Wth of atoms for have the same temperature. I don't lost energy of heating but I have recover energy from mouvment of the ball. And even it's not possible to recover energy from temperature I think it's not possible, so where the energy is lost ?
Second: I take a macroscopic system and try to find where the energy is lost. I don't find...
 
  • #9
I don't follow what you mean by..

when the ball move up in water, we recover energy PV (p=external pressure and V=volume of ball).

You need to state any assumptions made such as

The walls are thin/rubber so the volume can change in response to changing pressure
The temperature is changing/constant?

If the pressure falls and the volume increases P*V might be constant.

PV=nKT

if temperature is constant the P*V is constant.
 
  • #10
Why energy is PV ? because at top if I want to return ball (without change its temperature) I need P*V energy. Where the pressure falls ? At top the ball is in 0 pressure (vacuum)

Temperature changing/constant ? For me the internal temperature of ball don't change during move up. The external temperature change because water move up but after water move down so for me all temperature is constant. And this is for that I have a problem
 

1. What is the definition of energy in a system like a barometer?

Energy in a system like a barometer refers to the total amount of potential and kinetic energy present within the system. In a barometer, this includes the potential energy of the fluid due to its height and the kinetic energy of the fluid as it moves through the system.

2. How does the sum of energy change in a barometer system?

The sum of energy in a barometer system remains constant, according to the law of conservation of energy. This means that the total amount of energy in the system cannot be created or destroyed, only transferred between different forms.

3. What is the role of gravity in the sum of energy in a barometer system?

Gravity plays a crucial role in the sum of energy in a barometer system. It provides the potential energy of the fluid due to its height and also causes the fluid to move through the system, converting potential energy into kinetic energy.

4. How is the sum of energy calculated in a barometer system?

The sum of energy in a barometer system can be calculated using the formula: E = mgh + 1/2mv^2, where E is the total energy, m is the mass of the fluid, g is the acceleration due to gravity, h is the height of the fluid, and v is the velocity of the fluid.

5. How does the sum of energy in a barometer system affect atmospheric pressure?

The sum of energy in a barometer system is directly related to atmospheric pressure. As the sum of energy increases, the atmospheric pressure also increases, and vice versa. This is because the mass and height of the fluid in the barometer directly affect both the potential and kinetic energy present in the system.

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