Summing a series on an interval of convergence

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SUMMARY

The series in question is given by the formula \(\sum^{\infty}_{n=0}\frac{(x-1)^{2n}}{4^n}\). The interval of convergence is determined using the ratio test, yielding the result \(-1 < x < 3\). To find the sum of the series within this interval, one can apply the geometric series formula, recognizing that the series can be expressed in that form.

PREREQUISITES
  • Understanding of the ratio test for convergence
  • Familiarity with geometric series and their summation
  • Basic knowledge of series and sequences in calculus
  • Ability to manipulate algebraic expressions involving powers
NEXT STEPS
  • Review the ratio test for determining convergence of series
  • Study the formula for summing geometric series
  • Explore endpoint analysis for convergence intervals
  • Practice problems involving power series and their convergence
USEFUL FOR

Students studying calculus, particularly those focusing on series and convergence, as well as educators looking for examples of geometric series applications.

c.dube
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Homework Statement


Find the interval of convergence of the series and, within this interval, the sum of the series as a function of x.
[tex]\sum^{\infty}_{n=0}\frac{(x-1)^{2n}}{4^n}[/tex]

Homework Equations


N/A

The Attempt at a Solution


Finding the interval is easy, using the ratio test it reduces down to
[tex]|\frac{(x-1)^{2}}{4}|<1[/tex]
[tex]-1<x<3[/tex]

However, I have no idea how to do the second part. Any help?
 
Last edited:
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1- You should check the end points to decide the interval.
2- For the sum, I think you know something called "geomtric series", right?
 
Duh! Thanks.
 

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