Supersonic Jet: Mach 3 at Altitude 20,000m - Shock Wave & Boom Times

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Homework Help Overview

The problem involves a supersonic jet traveling at Mach 3 at an altitude of 20,000 meters, focusing on the timing of when a person on the ground will encounter the shock wave generated by the jet. The original poster seeks assistance specifically with determining the time of encounter with the shock wave.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between the altitude and the speed of the shock wave to determine the time it takes for the shock wave to reach the observer. Some question the assumptions made about the equations used and the cancellation of variables.

Discussion Status

Some participants have provided insights on calculating the time based on the altitude and speed of sound, while others have shared thoughts on the physical characteristics of shock waves and their relation to object shapes. There appears to be a mix of interpretations regarding the approach to the problem.

Contextual Notes

The discussion includes references to the speed of sound in air and the specific conditions under which shock waves are generated. There are also mentions of the original poster's previous work on part "b" of the problem, indicating a partial understanding of the overall context.

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Homework Statement



A supersonic jet traveling at Mach 3.00 at an altitude of 20,000 meters is directly over a person at a time t=0 as show in figure (see below). (a) At what time will the person encounter the the shock wave? (b) Where will the plane be when the "boom" is finally heard? (Assume the speed of sound in air is 335 m/s).

IMG_1395.jpg


This is a two part problem (a & b) and I need help with part "a" only as I've already solved part "b" on my own so far.

Homework Equations



IMG_1396.jpg


The Attempt at a Solution



Well, I solved part "b" by using sin = V/Vs with V = 1 Mach and Vs = 3 Mach to get the angle ( 19.5 degrees )

Then I used Tan = y/x solving for "x" with y=20,000 meters and Tan 19.5 degrees to get 5.66x10^4 meters.

Now for part "a" I don't have a clue how to get the time since wouldn't they just cancel out anyways by looking at the equation? I've obviously ruled out kinematics equations so...yeah.
 
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Well, if the shock wave is generated when the plane is directly above the person, the time it will take to reach him would just be h/the speed of the shock wave, no?
 
entorm said:
Well, if the shock wave is generated when the plane is directly above the person, the time it will take to reach him would just be h/the speed of the shock wave, no?

Ha...I totally missed that. I used d=rt and got the time.

Thanks!
 
The nose of the super sonic missile and rocket are of blunt shape to form a bow shock wave, why?
 
Any object moving in a fluid with a speed that exceeds the sound speed of the fluid creates a shock wave, and the shape of the shock wave depends on the shape of the object. I am not an expert on missiles or rockets, but I have the impression that their noses are actually sharp, and they are designed this way to minimize air resistance.
 

no u r not right,they have blunt nose to create bow shock wave. it has to do some thing with local heating
 
no u r not right,they have blunt nose to create bow shock wave. it has to do some thing with local heating
 

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