1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Surface area of intersecting cylinder and sphere

  1. Jul 30, 2008 #1
    I have a problem that I've been stuck on for a while as follows,

    Find the surface area of the part of the cylinder [tex]x^{2}+y^{2}=2ay[/tex] in the first octant that lies inside the sphere [tex]x^{2}+y^{2}+z^{2}=4a^{2}[/tex]. Express your answer in terms of a single integral in [tex]\phi[/tex], you do not need to evaluate this integral.

    I've started by parametrization the cylinder as [tex]S(\theta,z)=(\sqrt{2ay}cos(\theta),(\sqrt{2ay}sin(\theta),z)[/tex]. I then went on take the derivative of S in terms of [tex]\theta[/tex] and z and took the cross product of the terms. I know the bounds of integration for [tex]\theta[/tex] should be 0 to Pi/2, but from there I'm unsure of what to do in terms of setting up the bounds for z.

    Any help would be appreciated, thanks!
  2. jcsd
  3. Jul 30, 2008 #2


    User Avatar
    Homework Helper

    That looks more like an ellipse than a circle in the x-y plane. There is a special parametrisation for ellipses, but you have to express the equation in the form of an ellipse first. Secondly, your parametrisation for [tex]S(\theta,z)[/tex] is incorrect. It is supposed to consist only of [tex]\theta,z[/tex] and other constants. It shouldn't have y as a variable.
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?