Surface Area of Rotated Curve y=1+5x2 | x=0 to x=8

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SUMMARY

The discussion focuses on calculating the surface area of the curve defined by the equation y=1+5x², rotated about the y-axis from x=0 to x=8. The integral formula used is As=∫2πg(x)√(1+[g'(x)]²)dx, with limits adjusted to y=1 and y=321. A participant suggests an alternative approach using the integral ∫2πx√(1 + g'(x)²)dx, indicating a more straightforward method for solving the problem.

PREREQUISITES
  • Understanding of integral calculus, specifically surface area calculations.
  • Familiarity with the concept of rotating curves around axes.
  • Knowledge of derivatives and their application in integrals.
  • Ability to manipulate limits of integration for different axes.
NEXT STEPS
  • Study the derivation and application of the surface area integral formula As=∫2πg(x)√(1+[g'(x)]²)dx.
  • Learn how to change limits of integration when rotating curves about different axes.
  • Explore alternative methods for solving complex integrals, such as numerical integration techniques.
  • Investigate the implications of using different coordinate systems in surface area calculations.
USEFUL FOR

Students and educators in calculus, mathematicians focused on integral applications, and anyone interested in geometric interpretations of functions and their rotations.

danielatha4
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Homework Statement


Find the area of the surface obtained by rotating the curve y=1+5x2 from x=0 to x=8 about the y-axis



Homework Equations


As=[tex]\int[/tex]2[tex]\pi[/tex]g(x)sqrt(1+[g'(x)]2)


The Attempt at a Solution


I changed the limits to suit the y direction, the lower limit becomes 1 and the upper 321. I solved x as a function of y in order to rotate around the y-axis and when I plug everything into the formula is becoems a really messy integral I can't solve. I'm sure there's an easier way.
 
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Hi danielatha4! :smile:

Why not just use ∫ 2πx √(1 + g'(x)2) dx ?
 

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