Surface Area of Cylinder Bounded by x^2 + y^2 = a^2

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The discussion focuses on finding the surface area of a cylinder defined by the equation y^2 + z^2 = a^2, constrained by x^2 + y^2 = a^2. The user expresses uncertainty about setting up the double integral and determining the appropriate boundaries for polar coordinates. They attempted to derive the surface area using the formula A(S) = ∫∫ sqrt(1 + 4y^2 + 4z^2) dA but struggled with the integration limits. The conversation emphasizes the need for clarity on the boundaries in polar coordinates to proceed with the calculation. Overall, the thread highlights the challenges faced in applying integration techniques to solve the problem.
s_engineering
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Find the surface area of the the portions of the cylinder y^2 + z^2=a^2 bounded by x^2 + y^2 = a^2


not really sure how to go about this. tried to set up a double integral and use polar coordinates but don't know what boundaries to use etc.
 
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Hi s_engineering! Welcome to PF! :wink:

Show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 
this is what I've tried:

fy = 2y; fz=2z

A(S)=int int sqrt{1+4y^2 +4z^2}dA

then I switched to polar coordinates i tired to integrate from theta=0 to pi/2 and r= 0 to a
but didn't get anywhere with this.
 

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