dorothy
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- 1
- Homework Statement
- Does anyone knows how to solve these questions? Thanks a lot!
- Relevant Equations
- v=u+at
s=ut+1/2at^2
v^2=u^2+2as
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In part c, how far up the plane does the box go? What is its velocity at this point?dorothy said:Homework Statement:: Does anyone knows how to solve these questions? Thanks a lot!
Relevant Equations:: v=u+at
s=ut+1/2at^2
v^2=u^2+2as
View attachment 299486
Hi, I want to whether my answers on a & b are correct or not? For (c), I don’t really get the question, like what is the point of projection? How’s the deceleration and acceleration do in this case (c)? Thank you.Orodruin said:You seem to already have solved everything except (c), for which you have not shown any effort. What are your own thoughts regarding (c)?
Before that, I want to ask whether I understand question8 correctly? Is it true that there is a guy throwing(projecting) a box horizontally and the box finally land on the inclined plane(like what I have drawn)? Thank you.Chestermiller said:In part c, how far up the plane does the box go? What is its velocity at this point?
I don't agree with your answer to a). Acceleration is a vector, not a scalar.dorothy said:Hi, I want to whether my answers on a & b are correct or not?
Should (a) be -4.905?PeroK said:I don't agree with your answer to a). Acceleration is a vector, not a scalar.
This also affects the answer I would give to b) i) I).
Thaty said, it's not clear that the question setter acknowledges that acceleration is a vector.
That's what I would put. With the units as you have in your answer.dorothy said:Should (a) be -4.905?
I see. What about (b)? Are all of them correct?PeroK said:That's what I would put. With the units as you have in your answer.
I don't agree with b i) I).dorothy said:I see. What about (b)? Are all of them correct?
I expect the exercise composer means ##5## m/s along the incline, not ##5## m/s in a horizontal diertion.dorothy said:Before that, I want to ask whether I understand question8 correctly? Is it true that there is a guy throwing(projecting) a box horizontally and the box finally land on the inclined plane(like what I have drawn)? Thank you.
View attachment 299489
PeroK said:I don't agree with b i) I).
Sorry I meant b ii) I.dorothy said:May I know why bi) is not correct? I don’t know how to do it.
So higher acceleration gives smaller distance traveled until it turns around ... as OP stated.PeroK said:Sorry I meant b ii) I.
The acceleration has a greater magnitude in this case.
But if i assume the theta is 45° (which is greater than 30°, tilited more), then i put it into -9.81sin45°. I get the new acceleration=-6.9ms^-2. Next, I put 6.9 into the equation and get the new max distance =1.8 which is smaller than the original 2.55PeroK said:Sorry I meant b ii) I.
The acceleration has a greater magnitude in this case.
That right. It's like having more powerful brakes: you stop in a shorter distance.dorothy said:But if i assume the theta is 45° (which is greater than 30°, tilited more), then i put it into -9.81sin45°. I get the new acceleration=-6.9ms^-2. Next, I put 6.9 into the equation and get the new max distance =1.8 which is smaller than the original 2.55
So if the plane is tilited more, it becomes steeper, the distance traveled will also become smaller. Does it mean that I am actually correct on bii)1)?Orodruin said:So higher acceleration gives smaller distance traveled until it turns around ... as OP stated.
Does it mean that bii) I) is correct ?PeroK said:That right. It's like having more powerful brakes: you stop in a shorter distance.
Yes, sorry. I thought b ii) I was asking about the acceleration. I see now it's asking about the distance travelled.dorothy said:Does it mean that bii) I) is correct ?
No worries :) For part c, can you explain to me what is the meaning of reaching the point of projection? I don’t know which point it is. I’m super confused nowPeroK said:Yes, sorry. I thought b ii) I was asking about the acceleration. I see now it's asking about the distance travelled.
It was my fault.dorothy said:No worries :) For part c, can you explain to me what is the meaning of reaching the point of projection? I don’t know which point it is.
Probably the point where it was released with the original speed, but on the way down.dorothy said:No worries :) For part c, can you explain to me what is the meaning of reaching the point of projection? I don’t know which point it is. I’m super confused now
PeroK said:It was my fault.
I can only imagine that it means back at the bottom of the incline!