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- Homework Statement
- Does anyone knows how to solve these questions? Thanks a lot!
- Relevant Equations
- v=u+at
s=ut+1/2at^2
v^2=u^2+2as
Last edited:
In part c, how far up the plane does the box go? What is its velocity at this point?Homework Statement:: Does anyone knows how to solve these questions? Thanks a lot!
Relevant Equations:: v=u+at
s=ut+1/2at^2
v^2=u^2+2as
View attachment 299486
Hi, I want to whether my answers on a & b are correct or not? For (c), I don’t really get the question, like what is the point of projection? How’s the deceleration and acceleration do in this case (c)? Thank you.You seem to already have solved everything except (c), for which you have not shown any effort. What are your own thoughts regarding (c)?
Before that, I want to ask whether I understand question8 correctly? Is it true that there is a guy throwing(projecting) a box horizontally and the box finally land on the inclined plane(like what I have drawn)? Thank you.In part c, how far up the plane does the box go? What is its velocity at this point?
I don't agree with your answer to a). Acceleration is a vector, not a scalar.Hi, I want to whether my answers on a & b are correct or not?
Should (a) be -4.905?I don't agree with your answer to a). Acceleration is a vector, not a scalar.
This also affects the answer I would give to b) i) I).
Thaty said, it's not clear that the question setter acknowledges that acceleration is a vector.
That's what I would put. With the units as you have in your answer.Should (a) be -4.905?
I see. What about (b)? Are all of them correct?That's what I would put. With the units as you have in your answer.
I don't agree with b i) I).I see. What about (b)? Are all of them correct?
I expect the exercise composer means ##5## m/s along the incline, not ##5## m/s in a horizontal diertion.Before that, I want to ask whether I understand question8 correctly? Is it true that there is a guy throwing(projecting) a box horizontally and the box finally land on the inclined plane(like what I have drawn)? Thank you.
View attachment 299489
I don't agree with b i) I).
Sorry I meant b ii) I.May I know why bi) is not correct? I don’t know how to do it.
So higher acceleration gives smaller distance traveled until it turns around ... as OP stated.Sorry I meant b ii) I.
The acceleration has a greater magnitude in this case.
But if i assume the theta is 45° (which is greater than 30°, tilited more), then i put it into -9.81sin45°. I get the new acceleration=-6.9ms^-2. Next, I put 6.9 into the equation and get the new max distance =1.8 which is smaller than the original 2.55Sorry I meant b ii) I.
The acceleration has a greater magnitude in this case.
That right. It's like having more powerful brakes: you stop in a shorter distance.But if i assume the theta is 45° (which is greater than 30°, tilited more), then i put it into -9.81sin45°. I get the new acceleration=-6.9ms^-2. Next, I put 6.9 into the equation and get the new max distance =1.8 which is smaller than the original 2.55
So if the plane is tilited more, it becomes steeper, the distance traveled will also become smaller. Does it mean that I am actually correct on bii)1)?So higher acceleration gives smaller distance traveled until it turns around ... as OP stated.
Does it mean that bii) I) is correct ?That right. It's like having more powerful brakes: you stop in a shorter distance.
Yes, sorry. I thought b ii) I was asking about the acceleration. I see now it's asking about the distance travelled.Does it mean that bii) I) is correct ?
No worries :) For part c, can you explain to me what is the meaning of reaching the point of projection? I don’t know which point it is. I’m super confused nowYes, sorry. I thought b ii) I was asking about the acceleration. I see now it's asking about the distance travelled.
It was my fault.No worries :) For part c, can you explain to me what is the meaning of reaching the point of projection? I don’t know which point it is.
Probably the point where it was released with the original speed, but on the way down.No worries :) For part c, can you explain to me what is the meaning of reaching the point of projection? I don’t know which point it is. I’m super confused now
It was my fault.
I can only imagine that it means back at the bottom of the incline!