Sway Frame, Stuck with finding sway factor (Moment Distrubution)

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SUMMARY

The discussion focuses on calculating the sway factor for a beam with pinned joints using moment distribution methods. The key equation provided for fixed ends is Moment (AB) = 6EI(delta)/L², while the moment for pinned joints, such as CF, is assumed to be zero. The user has already determined a propping force of 42.25 kN and notes that for uniform lengths and EI values, the moment can be simplified to 3EI(delta)/L². This information is crucial for completing the distribution table in sway analysis.

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  • Understanding of moment distribution methods in structural analysis
  • Familiarity with beam theory and properties (EI, lengths)
  • Knowledge of pinned joint behavior in structural systems
  • Basic proficiency in calculating forces and moments in beams
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Structural engineers, civil engineering students, and professionals involved in beam analysis and sway factor calculations will benefit from this discussion.

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Homework Statement


I have a sway case beam as in the image below, but do not know the equation for the pinned joints.

We were told Moment (AB) = 6EI(delta)/Lsquared
for fixed ends such as AB and BA but not told the moment equation for CF for example.

I am assuming FC = 0 due to no moment at the pin but I cannot go further with my distribution table before knowing these values.

Edit: I have the proping force of 42.25kN already and everything before this, we were told to use an abitory moment but this was good in the example if all the lengths and EI's were the same.
 

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For anyone else needing to know this its 3ei(delta)/L squared :) and 0 for the pin.
 

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