# Shear Force Diagrams and Bending Moment Diagrams

## Homework Statement

http://img189.imageshack.us/img189/9131/22465062cfdd4934b51d7f5.png [Broken]

Hopefully the image isn't too difficult to decipher... Basically a beam balanced on to pin jointed pivots with 6 metres in between each one.

ƩFy = 0
ƩFx = 0
ƩMP = 0

## The Attempt at a Solution

I've solved the first section of the part...
The internal moment comes out to be -56kN/m
Axial Force is 0
And Shear Force is -6kN

Calculating the second section...
I'm stuck here, hence, why I don't think I can proceed with Section 3 either
I calculated the Internal Moment to be... 72 + v(6) kN/m (Which I think is wrong)..
The Shear Force came out to be -24kN
Axial Force is... 0?

Need help with completing the rest

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