Symbolic Expression for Speed of Draining a Tank

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SUMMARY

The discussion centers on deriving a symbolic expression for the speed of water draining from a tank, utilizing the differential equation A_b (dh/dt) = - A_o c √(2gh). The variables include h (height of water), A_b (area of the tank), A_o (area of the orifice), c (discharge coefficient, typically 0.62), and g (acceleration due to gravity). Additionally, the average discharge velocity, u(t), can be calculated using Torricelli's law, where u = c√(2gh). The average head of water remains ambiguous in the context provided.

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cruckshank
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Hi, I've completed an experiment in which I measured the height of the water in the tank with time. I plotted my results on graph paper as a graph of height against time, resulting in a curve of decreasing gradient, slightly resembling that of the e^(-kx) graph.

1) I am asked to symbolically suggest an expression for the speed at which the water level falls.

2) Additionally I am asked to use a simple technique to determine the average discharge velocity, u(t), and head of water h(t).

Thanks.
 
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Hi, welcome to PF!

1) Try solving the following differential equation, which is an unsteady state mass balance on the tank (works for rectangular or cylindrical tanks)
A_b \frac{dh}{dt} = - A_o c \sqrt{2gh}
Where h is the height of water in the tank, Ab is the area of the tank and Ao is the area of the orifice from which the water drains, c is called the discharge coefficient (usually 0.62 for this kind of systems), and g is the acceleration of gravity. The discharge velocity in this case, according to Torricelli's law is u=c\sqrt{2gh}.

2) For this case I would just use the numeric data to calculate the arithmetic mean of u using Torricelli's law. It is not clear to me what does the problem ask with average head of water.
 

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