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Symbolic Logic, Proof with Conditional

  1. May 29, 2010 #1
    2gwdguo.jpg

    Any advice on how to make step 6 check out?
     
  2. jcsd
  3. May 30, 2010 #2

    CompuChip

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    The problem is you can't conclude
    FrontOf(d, e)​
    from step 4, isn't it?
    Then isn't another quantifier elimination all you need (i.e. prove that Cube(e) and Dodec(d) implies FrontOf(d, e)) ?

    Also I'm wondering if you mixed up the order of e and y in step 4.
     
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