Find equation of the plane
The plane though P(6,3,2) and is perpendicular to vector <-2,1,5>
Why would it be -2(x - 6) + (y - 3) + 5(z - 2) = 0?
If it is perpendicular to <-2,1,5>, shouldn't be the cross product of some other vector with this? Using <-2,1,5> wouldn't mean it is parallel to the vector instead?