Tangent to ellipse also tangent to circle

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SUMMARY

The discussion focuses on finding the angle "theta" at which the tangent to the ellipse defined by the equation 16(x²) + 11(y²) = 256 is also tangent to the circle described by (x²) + (y²) + 2x = 15. The user attempts to derive the tangent line equation at point P(4 cos d, (16/sqrt(11)) sin d) and equates the perpendicular distance from the center of the circle C(-1, 0) to this tangent line to the circle's radius of 4. Despite a solid approach, the user encounters difficulties in solving for "theta" and seeks guidance to correct their method.

PREREQUISITES
  • Understanding of conic sections, specifically ellipses and circles
  • Knowledge of tangent lines and their equations
  • Familiarity with coordinate geometry and distance formulas
  • Ability to manipulate trigonometric functions
NEXT STEPS
  • Study the derivation of tangent lines to conic sections
  • Learn about the properties of ellipses and circles in coordinate geometry
  • Explore the concept of perpendicular distances from points to lines
  • Practice solving problems involving tangents to multiple conic sections
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Students studying advanced geometry, particularly those focusing on conic sections, as well as educators looking for examples of tangent line problems involving ellipses and circles.

sarthak sharma
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Homework Statement


if the tangent at a point P("theta") on the ellipse
16 (x^2) + 11 (y^2) = 256​
is also tangent to the circle
(x^2) + (y^2) + 2(x) = 15​
then ("theta") = ??

2. The attempt at a solution

{{{{ i have taken "theta" as "d" }}}}​

P [4 cos d , (16/(sqrt11)) sin d]

equation of tangent at P on ellipse is {(cos d) / 4] x + [(sin d) / (16/(sqrt11))] y = 1 .....(i)

centre of given circle C(-1,0) and radius r = 4

for (i) to also be tangent on the circle - perpendicular distance of (i) from C must be equal to 4

but when i tried to do so i could not get the answer
may be I am doing something wrong so please anyone could guide me the correct way
 
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sarthak sharma said:
but when i tried to do so i could not get the answer
The approach looks good, so please show your work so we can see what went wrong.
 

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