Tangent vector to curve of intersection of 2 surfaces

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To find the tangent vector at the point (1, 1, 2) for the curve of intersection of the surfaces z = x² + y² and z = x + y, one approach is to compute the gradients of both surfaces. The tangent vector can be determined by taking the cross product of these gradients, as they are normal to the tangent planes of the surfaces. It is important to ensure that the gradients are not parallel to obtain a valid tangent vector. The problem specifically requires only the direction of the tangent vector, simplifying the task. This method effectively utilizes the relationship between the surfaces and their gradients to find the desired vector.
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Homework Statement


Find the tangent vector at the point (1, 1, 2) to the curve of intersection of the surfaces z = x2 + y2 and z = x + y.

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The Attempt at a Solution


I haven't started the problem, because I'm not sure what the first thing to do is.
Do I have to parametrize the equations first? Then what?
 
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there's a couple of ways to do it... you could do it by finding a parametrisation of the curve..

an easier way woud be to notice that the tangent vector to the curve, will lie in both the tangent planes of the surfaces, then go form there
 
Oh!
If I find the gradient of each surface, and then cross the two gradients, that's it right?
 
yes, as the gradients will be normal to the tangent planes, and hopefully they are not parallel...

note that only the direction of the tangent vector is required in this case
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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